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siniylev [52]
3 years ago
13

3. You have decided to wallpaper your rectangular bedroom. The dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 i

nches high. The room has two windows, each 4 feet by 3 feet and a door 7 feet by 3 feet. Determine how many rolls of wallpaper are needed to cover the walls, allowing 10% for waste and matching. Each roll of wallpaper is 30 inches wide and 30 feet long. How many rolls of wallpaper should be purchased? * OA. 4 rolls OB. 5 rolls OC. 6 rolls OD. 7 rolls OE. 8 rolls
Mathematics
2 answers:
Jobisdone [24]3 years ago
6 0

Answer:

Correct answer is B. 5Rolls

Step-by-step explanation:

  1. First you have to put all values in same unit of measurement,

  • knowing that 1 foot=12 inches, we apply 3 rule:

12 inches is 1 feet

6 inches is 6/12 feet= 0,5 feet.

12 inches is 1 foot

30 inches is 30/12 feet=2,5feet.

2. Second,you have to calculate the total surface where you will wallpaper.

So you have to calculate the dimension of 2 different rectangles and substract the surfaces that you don't have to wallppaper (door and windows).

  • Let's calculate the surface of the rectancles. Let's put all units in feets.

Area rectangle 1 =10.5feet*8feet=84ft^{2} \\Area rectangle2=12.5feet*8feet=100ft^{2}\\Total Area of walls=(Area rectangle 1 *2) + (Area rectangle2*2)\\Total Area of walls=(84ft^{2} *2)+(100ft^{2})\\\\Total Area of walls=368ft^{2}

3. Now we have to calculate the area to substract from the total area, since you will not wallpaper the door and windows:

Windows=4feet*3feet*2=24ft^{2}  \\Door=7feet*3feet=21ft^{2}

4. Total area to wallpaper is Total surface of the room minus door and windows surface:

wallpaperArea=368ft^{2} -45ft^{2}\\wallpaperArea=323ft^{2}

5. Now you have to add 10% waste to the calculated surface:

323ft^{2} +(323*0.10)=355.3ft^{2}

6. So, you have the real area that will wallpaper considering 10% waste, it is 326.23 square feet. To calculate how many rolls you will need, you have to calculate the surface that each roll covers and then divide total surface by roll surface.

Roll surface=2,5feet*30feet=75feet^{2}

Rolls needed=355.3ft^{2}/75ft^{2}=4.73

7. As the number of rolls is not integer you have to round, then the answer is you will need 5 rolls of wallpaper.

Shalnov [3]3 years ago
5 0

Answer:

B. 5 rolls

Step-by-step explanation:

The areas of the room, not including the ceiling, are discriminated as follows:

Longer walls: (12.5\times8)\times2=200ft^2 (6 inches equals one foot)

Shorter walls: (10.5\times8)\times2 = 168ft ^ 2 (6 inches equals one foot)

Window area: (4\times3)\times2 = 24ft ^ 2

Door area: (7\times3) = 21ft ^ 2

Area that will be effectively covered:

Total area to wallpaper: 200 + 168 -24 -21 = 323ft ^ 2

Amount of paper needed: 323\times1.1 = 355.3ft ^ 2

30in = 24in + 6in = 2ft + 0.5ft = 2.5ft. That is, the area of ​​a roll of paper is 2.5\times30 = 75ft ^ 2

Number of rolls needed:

\frac{355.3}{75} = 4.73 rolls

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Step-by-step explanation:

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Volume of cylinder is 3 times of volume of cone having same base diameter and same height.

<u>Solution:</u>

Given that  

A cylinder and A cone have the same diameter = 10 inches and same height = 12 inches

Need to find the relationship between volume of cylinder and cone.

Let’s calculate volume of each object separately first.

<em><u>Calculation of volume of cylinder :</u></em>

Formula of volume of cylinder is given as:

V_{c y}=\pi r^{2} h

Where π=3.14

\text { radius } r=\frac{\text {diameter}}{2}=\frac{10}{2}=5 \text { inches }

height h = 12 inches  

On substituting given values in formula of cylinder we get

\begin{array}{l}{V_{c y}=3.14 \times 5^{2} \times 12=942 \text { cubic inches }} \\\\ {\text { Volume of cylinder }=V_{c y}=942 \text { cubic inches }}\end{array}

<em><u>Calculation of volume of cone:</u></em>

Formula of volume of cone is given as:

V_{c o}=\frac{\pi r^{2} h}{3}

Here π=3.14

\begin{array}{l}{\text { radius } r=\frac{\text { diameter }}{2}=\frac{10}{2}=5 \text { inches }} \\\\ {\text { height } \mathrm{h}=12 \text { inches }}\end{array}

On substituting given values in formula of cone we get

V_{c o}=\frac{3.14 \times 5^{2} \times 12}{3}=314 \text { cubic inches }

\text { Volume of cone }=V_{c o}=314 \text { cubic inches }

On comparing the two volumes we get  

V c y: V c o=942: 314=3: 1

Hence can conclude that Volume of cylinder is 3 times of volume of cone having same base diameter and same height.

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