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Hunter-Best [27]
2 years ago
9

PLS HELP ASAP with all four pictures

Mathematics
1 answer:
grandymaker [24]2 years ago
8 0

See below for the solution to each question

<h3>How to determine the type of event?</h3>

When each friend takes a fruit in the bowl, and they do not return it.

The probability of selecting that particular fruit has been reduced to 0 from 1/5.

This means that taking the fruit influences the other events

Hence, the event is a dependent event

<h3>Probability of selecting another black socks</h3>

We have:

Black = 6

Total = 12

P(First black) = 6/12

Now, we have:

Black = 5

Total = 11

P(Second black) = 5/11

Hence, the probability is 5/11

<h3>How to determine the type of event?</h3>

We have:

Event A = Vowel

Event B = A - E

A and E are vowels.

This means that

P(A and B) ≠ 0

Hence, the event is a dependent event

<h3>Probability of selecting green</h3>

We have:

Green = 1

Total = 6

P(Green) = 1/6

Hence, the probability is 1/6

<h3>Probability of selecting a black card</h3>

We have:

Black cards = 26

Total = 52

P(Black card) = 26/52

P(Black card) = 1/2

Hence, the probability is 1/2

<h3>How to determine the type of event?</h3>

We have:

Event A = Red card

Event B = Heart card

All heart cards are red cards

This means that

P(A and B) ≠ 0

Hence, the event is a dependent event

<h3>How to determine the type of event?</h3>

When an item is selected and nor returned, the event is a dependent event

Hence, the  dependent event is picking two marbles without replacement

<h3>When tossing a coin</h3>

The sample space of tossing two coins is

S = {HH, HT, TH, TT}

Hence, the event not in the sample space is H

<h3>Probability of red</h3>

We have:

Red = 2

Total = 12

P(Red) = 2/12

P(Red) = 1/6

Hence, the probability is 1/6

<h3>Probability of not heart</h3>

We have:

P(heart) = 1/4

P(Not heart) = 1 - 1/4

P(Not heart) = 3/4

Hence, the probability is 3/4

Read more about probability at:

brainly.com/question/25870256

#SPJ1

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