Answer:
Step-by-step explanation:
2.99548 * 1.8342
the first number rounds to 3.....the second number rounds to 2.....3 * 2 = 6...but it will be a little short of 6 because of the 1.8.....so I am going with 5.5
===============================
jada ran 7.1 miles.....noah ran 5.123 miles
so jada ran (7.1 - 5.123) = 1.977 miles farther then noah
===============================
greater then 3...
1.67 + 1.4 and 4.5 - 1.47
Answer:
a.) Between 0.5 and 3 seconds.
Step-by-step explanation:
So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.
If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.
Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.
So, the answer is a.) between 0.5 and 3 seconds.
Answer:
Length = Width * 3
Width = 2 ft
Length = 2 ft * 3 = 6 ft
Perimeter = (L * 2) + (W * 2)
P = 16 ft
Area = L * W = 12 square feet
Answer:
J(2, 5 )
Step-by-step explanation:
Using the section formula
=
=
=
= 2
=
=
=
= 5
Thus J = (2, 5 )
Answer:
355
Step-by-step explanation: