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Vesna [10]
2 years ago
6

On a coordinate plane, a curved line with minimum values of (negative 2, 0) and (1.05, negative 41), and a maximum value of (neg

ative 0.5, 5), crosses the x-axis at (negative 2, 0), (0, 0), and (1.5, 0), and crosses the y-axis at (0, 0).
Which statement is true about the end behavior of the graphed function?

As the x-values go to positive infinity, the function’s values go to positive infinity.
As the x-values go to zero, the function’s values go to positive infinity.
As the x-values go to negative infinity, the function’s values are equal to zero.
As the x-values go to negative infinity, the function’s values go to negative infinity.
Mathematics
1 answer:
loris [4]2 years ago
3 0

The statement which is true about the end behaviour of the graphed function is; As the x-values go to positive infinity, the function’s values go to positive infinity.

<h3>Which statement is true about the end behaviour of the graphed function?</h3>

The graph given according to the task content is described to have its first minimum at (-2,0), and then a maximum at; (-0.5, 5) and finally a minimum at; (1.05, -41).

Additionally, since the graph has 3 zeroes as given, it follows that the graph is that of a cubic function which takes the w-form.

Consequently, it can be inferred from the statements above that; As the x-values go to positive infinity, the function’s values go to positive infinity.

Read more on graph end behaviours;

brainly.com/question/12682603

#SPJ1

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Answer:

Step-by-step explanation:

2.99548 * 1.8342

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Step-by-step explanation:

So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.

If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.

Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.

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