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AlekseyPX
1 year ago
8

What operation is being done to the variable in the equation -5m = -40?

Mathematics
1 answer:
yaroslaw [1]1 year ago
6 0

Answer:

m=8

Step-by-step explanation:

-5m=-40

divide both side by -5

-5m=-40

-5=-5 answer is m=8

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C is the midpoint of ab. Ac = 5x-13, cb = 4x+7. What is the length of ac
krek1111 [17]
AC in this problem will equal 87. If the (units) is where you put the put units like feet, inches if there is units.

3 0
3 years ago
X + (2x + 5) = 3(x – 4)+7
eduard

Answer:

Not true

Step-by-step explanation:

x + (2x + 5) = 3(x – 4)+7

Opening bracket on left and side and distributing 3 over (x-4) on right hand side

x+2x+5=3x-3 x 4 + 7

adding like terms

3x+5=3x-12+7

3x+5=3x-5

Hence

5 = -5

Which is not possible , Hence the equation given to us is false.

5 0
3 years ago
A ship leaves port at 10 miles per hour, with a heading of N 35° W. There is a warning buoy located 5 miles directly north of th
Leno4ka [110]

The value of the angle subtended by the distance of the buoy from the

port is given by sine and cosine rule.

  • The bearing of the buoy from the is approximately <u>307.35°</u>

Reasons:

Location from which the ship sails = Port

The speed of the ship = 10 mph

Direction of the ship = N35°W

Location of the warning buoy = 5 miles north of the port

Required: The bearing of the warning buoy from the ship after 7.5 hours.

Solution:

The distance travelled by the ship = 7.5 hours × 10 mph = 75 miles

By cosine rule, we have;

a² = b² + c² - 2·b·c·cos(A)

Where;

a = The distance between the ship and the buoy

b = The distance between the ship and the port = 75 miles

c = The distance between the buoy and the port = 5 miles

Angle ∠A = The angle between the ship and the buoy = The bearing of the ship = 35°

Which gives;

a = √(75² + 5² - 2 × 75 × 5 × cos(35°))

By sine rule, we have;

\displaystyle \frac{a}{sin(A)} = \mathbf{ \frac{b}{sin(B)}}

Therefore;

\displaystyle sin(B)= \frac{b \cdot sin(A)}{a}

Which gives;

\displaystyle sin(B) = \mathbf{\frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }}

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx 37.32^{\circ}

Similarly, we can get;

\displaystyle B = arcsin\left( \frac{75 \cdot sin(35^{\circ})}{\sqrt{75^2 + 5^2 - 2 \times 75\times5\times cos(35^{\circ}) } }\right) \approx \mathbf{ 142.68^{\circ}}

The angle subtended by the distance of the buoy from the port, <em>C</em> is therefore;

C ≈ 180° - 142.68° - 35° ≈ 2.32°

By alternate interior angles, we have;

The bearing of the warning buoy as seen from the ship is therefore;

Bearing of buoy ≈ 270° + 35° + 2.32° ≈ <u>307.35°</u>

Learn more about bearing in mathematics here:

brainly.com/question/23427938

5 0
2 years ago
The function g(x) is a translation of f(x) = (x 3)2 – 10. The axis of symmetry of g(x) is 5 units to the right of f(x). Which fu
natali 33 [55]

The axis of symmetry of g(x) is 2 units right side from the origin then the function is \rm g(x) = (x - 2)^2 + k. Then the correct option is A.

<h3>What is a function?</h3>

The function is an expression, rule, or law that defines the relationship between one variable to another variable. Functions are ubiquitous in mathematics and are essential for formulating physical relationships.

Given

The function f(x) is (x+3)^2 - 10.

The axis of symmetry of f(x) is left side by 3 units.

The axis of symmetry of g(x) is 5 units to the right of f(x).

Then the axis of symmetry of g(x) is 2 units right side from the origin.

Then the g(x) will be

\rm g(x) = (x - 2)^2 + k

Thus, the correct option is A.

More about the function link is given below.

brainly.com/question/14674614

5 0
2 years ago
Please help, I don't get this
Alex

Answer:

The answer is c

Step-by-step explanation:

My college brother told me this is the answer if it isn't I'm sorry but it's his fault

8 0
3 years ago
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