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2 years ago

8

What is the perimeter of the are. Please show work.

1 answer:

Brilliant_brown [7]2 years ago

5 0

Answer:

p = 633.09 ft

Step-by-step explanation:

The distances of each leg are indicated

Add them to get the perimeter

p = 100 + 89.44 + 186.81 + 120.83 + 136.01

p = 633.09 ft

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2 years ago

A patio 2 pairs of two parallel sides and 2 pairs of sides that are the same length there are 4 square corners what shape is the

Tems11 [23]

Answer:

The patio is a rectangle

Step-by-step explanation:

Since it is given that we have 2 pairs of two parallel sides, which implies 4 sides, this thus shows that the shape is a quadrilateral since, only quadrilaterals have 4 sides. Also, 2 pairs of sides are the same length, and are parallel, it shows that the shape is likely a rectangle.

Finally, there are 4 square corners on the shape which implies 4 right angles. This confirms that our shape is a rectangle since only a rectangle has 2 pairs of two parallel sides and 2 pairs of sides that are the same length there are 4 square corners.

So, the patio is a rectangle.

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2 years ago

Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

2 years ago

A tin of biscuits contains shortbread and choc-chip biscuits in the ratio 2:3 . The tin contains 80 biscuits. How many short-bre

Aleksandr [31]

Answer:

32

Step-by-step explanation:

There are 80 biscuits inside the tin.

Also, they said that those biscuits are in the ratio

Short bread : Choc - chip

2 : 3

Altogether there are 5 shares ( 2 + 3)

And now you can divide 80 by 5 to find how many biscuits contain per a share.

80 ÷ 5 = 16

In the question, they asked us to to find the number of short biscuits inside the tin.

Let us find that.

There are 2 shares for short bread biscuits.

So,

Number of short biscuits ⇒ 2 × 16

⇒ 32

Hope this helps you :-)

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago