Answer: A small mailbag is released from a helicopter that is descending steadily at 1.53 m/s. Then,
a) after 4s, the speed of the mailbox will be, 40.73m/s downwards.
b)78.4m downwards.
c) v=37.67m/s downward. and d=78.4m downward.
Explanation: To find the answer, we need to know more about the equations of uniformly accelerated motion.
<h3>What are the equations of uniformly accelerated motion?</h3>
- The equations of uniformly accelerated motion under gravity are,
<h3>How to solve the problem?</h3>
- a) speed of the mailbag after 4s,
- b) How far it is below the helicopter,
- c) If the helicopter is rising steadily, then v and d will be,
Thus, we can conclude that, the answers to the question are, a) after 4s, the speed of the mailbox will be, 40.73m/s downwards.
b)78.4m downwards.
c) v=37.67m/s downward. and d=78.4m downward.
Learn more about the equation of uniformly accelerated motion here:
brainly.com/question/28044927
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