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2 years ago

Solve for n. F = 4/3 (n-1) The solution is n= F+

Mathematics

1 answer:

Arte-miy333 [17]2 years ago

6 0

$F=\dfrac{4}{3}(n-1)\ \ \ \ |\cdot\dfrac{3}{4}\\\\n-1=\dfrac{3}{4}F\ \ \ \ |+1\\\\\boxed{n=\dfrac{3}{4}F+1}$

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Solve for n. F = 4/3 ​(n-1) The solution is n= F+

Solve for n. F = 4/3 (n-1) The solution is n= F+