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Dmitry [639]
3 years ago
13

Solve for n. F = 4/3 ​(n-1) The solution is n= F+

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
6 0

F=\dfrac{4}{3}(n-1)\ \ \ \ |\cdot\dfrac{3}{4}\\\\n-1=\dfrac{3}{4}F\ \ \ \ |+1\\\\\boxed{n=\dfrac{3}{4}F+1}

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