Question

Solve for n. F = 4/3 ​(n-1) The solution is n= F+

Answer 1

$F=\dfrac{4}{3}(n-1)\ \ \ \ |\cdot\dfrac{3}{4}\\\\n-1=\dfrac{3}{4}F\ \ \ \ |+1\\\\\boxed{n=\dfrac{3}{4}F+1}$