Let p (x) = 4x^4-13x^2-2x
The zero of x-2 is 2
putting x = 2 in p (x), we get,
p (2) = 4×2^4-13×2^2-2×2
= 64 - 52 - 4
= 64 - 56
= 8
Therefore, remainder = 8
-5 = 3/4x - 2
-5 + 2 = 3/4x
-3 = 3/4x
-3 / (3/4) = x
-3 * 4/3 = x
-12/3 = x
-4 = x <==
Answer:
20 or D.
Step-by-step explanation:
You simply plug in the values given for a and b:

So, your answer is 20.
Given: f(x)=(2x-2)/4
find f^-1(3)?
we need to find the inverse of f(x), so
x=(2y-2)/4
2y-2=4x
y-1=2x
y=2x+1
so, then f^-1(x)=2x+1
f^-1(3)=2(3)+1
=6+1
=7
so, the answer is 7