Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Pls give this a 5 star rating lol
So what they are telling you is that 5 is three higher than the variable n.
So n = 5-3
so n is 2.
Step-by-step explanation:
Using the formulas
A
=
π
r
2
C
=
2
π
r
Solving for
A
A
=
C
2
4
π
=
117
2
4
·
π
≈
1089.33601
cm²
A
≈
1089.34
cm²
