Question

A coin is flipped 10 times and the result is recorded. How many outcomes are in the event n(A)?

Answer 1

Answer:

$1024$

Step-by-step explanation:

Each and every flip of our coin has two possible outcomes on the whole: it is either the heads or the tails. Besides, it resembles the bit in computing, right? Indeed, it has two options likewise: it can be either $0$ or $1$. For now on I suggest thinking neither in heads nor in tails, but in bits. Suppose the heads is $0$, the tails is $1$. Let us slightly simplify the condition, namely: suppose that the number of flips is $3$. Then, our possible outcomes:

$000 \\ 001 \\ 010 \\ 011 \\ 100 \\ 101 \\ 110\\ 111$

Take a look at the first number. In case it is $0$, we have $4$ outcomes because we can put either $0$ or $1$ not only on the second place, yet also on the third one. Abiding by the same logic, we also have $4$ outcomes when the first one is $1$. In mathematics: $2 * 2 * 2 = 2^3 = 8$ outcomes.
As for the initial condition, it does not globally differ from our simplification, it just has more flips, hence it is not just a walk in the park to list all the possible outcomes anymore in this case, it is time-consuming otherwise. Even though, it is still not a big deal to count it: $2 * ... * 2 = 2^{10} = 1024$ outcomes.

Answer 2

There are 1024 outcomes in the event

How to determine the number of outcomes?

The given parameters are:

Device = coin

Number of flips = 10

A coin has 2 faces.

So, the number of outcomes is

Outcome = Faces^Flip

This gives

Outcome = 2^10

Evaluate

Outcome = 1024

Hence, there are 1024 outcomes in the event

Read more about outcomes at:

brainly.com/question/12090187

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