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Alex777 [14]
3 years ago
8

4x-2y=7 -3x+3y=10 Find the point of intersection of the equations

Mathematics
2 answers:
Lemur [1.5K]3 years ago
6 0
  4x - 2y = 7   ⇒ -12x +   6y = -21
-3x + 3y = 10 ⇒ <u>-12x + 12y = 40</u>
                                       <u>-6y</u> = <u>-61</u>
                                        -6      -6
                                           y = 10¹/₆
                          4x - 2(10¹/₆) = 7
                                4x - 8¹/₃ = 7
                                <u>    + 8¹/₃ + 8¹/₃
</u>                                         <u>4x</u> = <u>15¹/₃
</u>                                          4        4<u>
</u>                                           x = 3⁵/₆
                                     (x, y) = (3⁵/₆, 10¹/₆)
garri49 [273]3 years ago
4 0
4x-2y=7 (1)
-3x+3y=10 (2)
3y= 3x+10
y= x+10/3 (3)
sub (3) into (1)
4x-2(x+10/3)=7
4x-2x-20/3=7
2x-20/3=7
    +20/3  +20/3
2x= 41/3
x= (41/3) / 2
x= 41/6
sub x= 41/6 into (3)
y= 41/6+10/3
= 61/6

Therefore the point of intersection is (41/6, 61/6) 
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Answer: 17.9

Step-by-step explanation:

Using Heron's formula:

Area of a triangle is given by:

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S = (a+b+c) / 2

In the question above sides are :

XY=XZ= 20 and YZ=18

S = (20 + 20 + 18) / 2 = 58/2 = 29

Area = √29(29-20)(29-20)(29-18)

Area = √29(9)(9)(11)

Area = √25839

Area = 160.74513

Altitude = height(h)

Area = 0.5 × base × height

Base = yz = 18

160.74513 = 0.5 × 18 × h

160.74513 = 9 × h

h = 160.74513 / 9

h = 17.9 (3 s.f)

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1/1

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Ainat [17]
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8 0
4 years ago
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Step-by-step explanation:

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