The circle is open on 2. shade right on the nimber line
Easy
y=a(x-h)^2+k
vertex is (h,k)
we know that vertex is (4,0)
input that point for (h,k)
y=a(x-4)^2+0
y=a(x-4)^2
passes thorugh the point (6,1)
input that point to find a
1=a(6-4)^2
1=a(2)^2
1=a(4)
divide both sides by 4
1/4=a
thefor the equation is
y=(1/4)(x-4)^2
or
y=(1/4)x^2-2x+4
Answer:
Step-by-step explanation:
<u>Ratios
</u>
We are given the following relations:
![a=\sqrt{7}+\sqrt{c}\qquad \qquad[1]](https://tex.z-dn.net/?f=a%3D%5Csqrt%7B7%7D%2B%5Csqrt%7Bc%7D%5Cqquad%20%5Cqquad%5B1%5D)
![b=\sqrt{63}+\sqrt{d}\qquad \qquad[2]](https://tex.z-dn.net/?f=b%3D%5Csqrt%7B63%7D%2B%5Csqrt%7Bd%7D%5Cqquad%20%5Cqquad%5B2%5D)
![\displaystyle \frac{c}{d}=\frac{1}{9} \qquad \qquad [3]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bc%7D%7Bd%7D%3D%5Cfrac%7B1%7D%7B9%7D%20%5Cqquad%20%5Cqquad%20%5B3%5D)
From [3]:
Replacing into [2]:
We can express 63=9*7:
Taking the square root of 9:
Factoring:
Find the ration a:b:
Simplifying:
Answer: 0.15km/min and 0.3km in 2 mins
Step-by-step explanation:
Given Data:
Cyclists speed = 9km/hr
1. Some traveling 60 km/h is traveling one km/min
60/60= 1 km/min
Rate in km/min
= 9km/hr / 60min
= 3/20 km/min
= 0.15 km/min
Kilometers travelled in 2mins
= 2 / 60
= 1 / 30
= 9km/hr * 1 / 30
= 9 / 30
= 0.3 km in 2mins
