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Lerok [7]
2 years ago
6

If a is an obtuse angle in a triangle and sin a = , calculate the exact value of sin 2a.

Mathematics
1 answer:
garik1379 [7]2 years ago
8 0

Answer:

Step-by-step explanation:

cos A = √( 1 - (5/13)²) = √( 1 - 25/169) = √(144/169) = - 12 /13

in 2 A = 2 sin A cos A

sin 2 A = 2 *5/13 ( - 12/13 ) = - 120 / 169

the answer is -120/169

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Mr. Malone is contemplating which chauffeured car service to take to the airport. The first costs $28 upfront and $2 per mile. T
Ksju [112]

Answer:

The distance is 8 miles.

Step-by-step explanation:

First, we need to write an equation for each of chauffeured car services.

The first one = 28 + 2x = ?

The second one = 13 + 5x = ?

Next, we need to figure out what x is. Usually I just plug in random numbers, but I'm sure there's a better way to do it.

I first plugged in 2 as x.

28 + 4 = 32

13 + 10 = 23

That didn't work, so I then plugged in 5.

28 + 10 = 38

13 + 25 = 38

So 5 would be the correct answer for what is the distance.

8 0
3 years ago
I need help on this if you know all the answers that would be great but if not I understand I am just struggling
tatyana61 [14]

Answer:

1. 8x+9

2. 3x + 11

3. 9x + 8

4. 11x+9

5. 6x

6. 10x+ 8

7. 7x+7

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What option is correct: A or B
Yuliya22 [10]
The image isn’t visible. Would recommend reposting
5 0
3 years ago
HELP ASAP!!! 40 POINTS
ICE Princess25 [194]

Using derivatives, it is found that the x-values in which the slope belong to the interval (-1,1) are in the following interval:

(-15,-10).

<h3>What is the slope of the tangent line to a function f(x) at point x = x0?</h3>

It is given by the derivative at x = x0, that is:

m = f^{\prime}(x_0).

In this problem, the function is:

f(x) = 0.2x^2 + 5x - 12

Hence the derivative is:

f^{\prime}(x) = 0.4x + 5

For a slope of -1, we have that:

0.4x + 5 = -1

0.4x = -6

x = -15.

For a slope of 1, we have that:

0.4x + 5 = 1.

0.4x = -4

x = -10

Hence the interval is:

(-15,-10).

More can be learned about derivatives and tangent lines at brainly.com/question/8174665

#SPJ1

8 0
2 years ago
The coordinates of AB are A(-5, -1) and B(-2, -6). If AC : CB = 3 : 7, what are the coordinates of point C?
navik [9.2K]

\text{Let the coordinates of AB are }A(-5,-1), \text{ and }B(-2, -6)\\&#10;\\&#10;\text{let the coordinate of th point C be (x, y), such that}\\&#10;\\&#10;AC:CB=3:7\\&#10;\\&#10;\text{By the section formula, we know that if P(x,y) lies on a line segment AB}\\&#10;\text{where, }A(x_1,y_1), \ B(x_2,y_2)\text{ and satisfy the ratio, }AP:PB=m:n, \text{ then}

P=\left ( \frac{mx_2+nx_1}{m+n}, \ \frac{my_2+ny_1}{m+n} \right ).\\&#10;\\&#10;\text{So using this formula, we get for the given problem}\\&#10;\\&#10;C=\left ( \frac{3(-2)+7(-5)}{3+7}, \ \frac{3(-6)+7(-1)}{3+7} \right )\\&#10;\\&#10;\Rightarrow C=\left ( \frac{-6-35}{10}, \ \frac{-18-7}{10} \right )\\&#10;\\&#10;\Rightarrow C=\left ( \frac{-41}{10}, \ \frac{-25}{10} \right )\\&#10;\\&#10;\Rightarrow C=\left ( -4.1, \ -2.5 \right )

Coordinates of the point C is: (-4.1, -2.5)

5 0
4 years ago
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