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2 years ago

All numbers less than 7 and greater than 7

Mathematics

1 answer:

mrs_skeptik [129]2 years ago

4 0

Step-by-step explanation:

123456 less then 7

unlimited greater then 7

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Can you please help with multiplication and division equations

Bad White [126]

#1.) 9
2.) 6
3.) 3
4.) 24

2a.) 7 2b.) 18 2c.) 13

7 0

3 years ago

Look at the photo plz !!

sergejj [24]

Answer:

11 0ver 54

Step-by-step explanation:

4 0

3 years ago

If the ratio for unit cost to sales price for a product is 1:4, how much would the selling price be for a product if it has a un

Over [174]

Unit cost to sales price is 1:4.....or 1/4

1 / 4 = 33.85 / s.....1 unit cost to 4 sales price = 33.85 unit cost = s sales price
cross multiply
(1)(s) = (4)(33.85)
s = 135.40 <=== selling price

3 0

4 years ago

Read 2 more answers

A monument in the shape of a right triangle sits on a rectangular pedestarl that is 7 meters high by 16 meters long. The longest

Minchanka [31]

Answer: 70 meters

Step-by-step explanation:

Hi, since the situation forms a right triangle and a rectangle, we have to apply the Pythagorean Theorem (for the triangle)

c^2 = a^2 + b^2

Where c is the hypotenuse of the triangle (the longest side) and a and b are the other sides.

Replacing with the values given:

65^2 = 16^2 + x^2

4,225 = 256 + x^2

4,225-256 = x^2

3,969=x^2

√3,969 =x

63=x

We have calculated the missing side of the triangle, now we have to add the height of the rectangle:

63 +7 =70 meters

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

The sum of four consecutive terms of an arithmetic progression is 32 and the ratio of product of the first and the last term to

OverLord2011 [107]

The four consecutive terms are 2,6,10,14.

Explanation:

Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)

It is given that the sum of four consecutive terms is 32.

Thus, adding all the four consecutive terms, we have,

$\begin{array}{r}{a-3 d+a-d+a+d+a+3 d=32} \\{4 a=32} \\{a=8}\end{array}$

Thus, the value of a is 8.

It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,

$\frac{(a-3d)(a+3d)}{(a-d)(a+d)} =\frac{7}{15}$

Simplifying the terms, we have,

$\begin{aligned} \frac{a^{2}-9 d^{2}}{a^{2}-d^{2}} &=\frac{7}{15} \\ 15\left(a^{2}-9 d^{2}\right) &=7\left(a^{2}-d^{2}\right) \\ 15 a^{2}-135 d^{2} &=7 a^{2}-7 d^{2} \\ 8 a^{2} &=128 d^{2} \end{aligned}$

Now, substituting a = 8, we have,

$\begin{aligned} 8(64) &=128 d^{2} \\ 512 &=128 d^{2} \\ 4 &=d^{2} \\ 2 &=d \end{aligned}$

Thus, the value of d is 2.

Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.

Thus, the four consecutive terms are 2,6,10,14.

8 0

3 years ago