Answer:
A.) 48%
Explanation:
AA = dominant genotype
Aa = heterozygous genotype
aa = recessive genotype
Hardy-Weinberg Equations:
p² + 2pq + q² = 1 p + q = 1
In this equation, In this equation,
-----> p² = frequency of "AA" -----> p = frequency of "A"
-----> 2pq = frequency of "Aa" -----> q = frequency of "a"
-----> q² = frequency of "aa"
(Step 1)
Determine the frequency of the recessive allele ("a").
72 / 200 = 0.36 recessive phenotype
The only way to have the recessive phenotype is to have the recessive genotype, aa. Therefore, q² = 0.36.
If q² = 0.36, then q = 0.6 (take the square root).
(Step 2)
Determine the frequency of the dominant allele ("A").
p + q = 1
p + 0.6 = 1
p = 0.4
(Step 3)
Determine the frequency of the heterozygous genotype ("Aa").
If -----> p = 0.4 and q = 0.6
Then -------> 2pq = 2(0.4)(0.6) = 0.48
0.48 x 100% = 48% Aa
