Question

AP Biology - If 72 out of 200 individuals....(pic is attached) - worth 25 points!

Answer 1

Answer:

A.) 48%

Explanation:

AA = dominant genotype

Aa = heterozygous genotype

aa = recessive genotype

                            Hardy-Weinberg Equations:

p² + 2pq + q² = 1                                                  p + q = 1

In this equation,                                                  In this equation,

-----> p² = frequency of "AA"                               -----> p = frequency of "A"

-----> 2pq = frequency of "Aa"                            -----> q = frequency of "a"

-----> q² = frequency of "aa"

(Step 1)

Determine the frequency of the recessive allele ("a").

72 / 200 = 0.36 recessive phenotype

The only way to have the recessive phenotype is to have the recessive genotype, aa. Therefore, q² = 0.36.

If q² = 0.36, then q = 0.6 (take the square root).

(Step 2)

Determine the frequency of the dominant allele ("A").

p + q = 1

p + 0.6 = 1

p = 0.4

(Step 3)

Determine the frequency of the heterozygous genotype ("Aa").

If -----> p = 0.4 and q = 0.6

Then -------> 2pq = 2(0.4)(0.6) = 0.48

0.48 x 100% = 48% Aa