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2 years ago

The set of all months that contain less than 31 years

Mathematics

1 answer:

ale4655 [162]2 years ago

4 0

The set of all months that contains less than 31 days is; {February, April, June, September, November}.

<h3>What is the set of all months that contain less than 31 days?</h3>

It follows from the task content that the set whose elements are to be determined is characterized by containing less than 31 days.

On this note, it follows that the elements of the set are; February (28/29 days), April (30 days), September (30 days), June (30 days) and November (30 days).

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salantis [7]

Answer:

1 3/5 miles/hr

Step-by-step explanation:

Let C be the speed of the current

Let D be the distance between Chan's house and the park

We know that Distance, D, is = Speed x Time

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Chan's speed going upstream is (8 - C)mph.

That gives us:

D = (8-C)(3 hr)

Chan's speed going downstream is (8+C)mph

So we have:

D = (8+C)(2 hr)

We know that the d is the same for these two equations, so:

(8-C)(3 hr) = (8+C)(2 hr)

24 - 3C = 16 + 2C

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C = (8/5) or 1 3/5 mph

5 0

2 years ago

Read 2 more answers

Carter answered 5% of the questions

Ipatiy [6.2K]

Answer:19/20

1-20=19

1÷20=0.05

0.05=5%

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4 0

3 years ago

A vase has the shape of a rectangular prism. The inside of the vase is also a rectangular prism. What is the volume of the solid

saw5 [17]

Answer:

$V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)$

Step-by-step explanation:

The geometric description of the vase is described in the image attached below. The volume of the solid part of the vase is:

$V_{s} = V_{out} - V_{in}$

$V_{s} = \frac{\pi}{4}\cdot D_{out}^{2} \cdot h -\frac{\pi}{4}\cdot (D_{out}-2\cdot t)^{2}\cdot (h-t)$

Where:

$D_{out}$ - Outer diameter, in centimeters.

$t$ - Vase thickness, in centimeters.

3 0

3 years ago

What is the solution for line one: y=-2x+1 line two: -2x-3

Oliga [24]

The slope-intercept form is

y=mx+b

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6 0

3 years ago

Read 2 more answers

Thulani goes to the library every 7 days. He goes to the market every 4 days

emmasim [6.3K]

Thulani goes to both the library and the market for 5 more times during the year.

Step-by-step explanation:

Thulani goes to the library every 7 days. He goes to the market every 4 days.

We have to calculate the Least Common Multiple (LCM) to analyze the next common day on which he will go to both places.

The factors of 7 are: 1 x 7

The factors of 4 are: 2 x 2

Therefore, the LCM would be = 1 x 7 x 2 x 2

LCM = 28

LCM indicates that Thulani will go to both places on every 28th day.

To calculate the number of times (n) he will go to both places on same day. We can use the formula mentioned below:'

$n = \frac{Number of days}{frequency}$

Here frequency represents the LCM = 28.

The number of days are:

August: 30 (we are excluding 1st August)

September: 30

October: 31

November: 30

December: 31

Total = 152

By putting the values in formula, we get

$n = \frac{152}{28}$

n = 5.42

As, the number of times can only be a whole number. Therefore, Thulani goes to both the library and the market for 5 more times during the year.

Learn more:

The following links have more information

brainly.com/question/12419898

brainly.com/question/12764620

Keywords: LCM, same day

#learnwithBrainly

7 0

3 years ago