Answer:
Assuming the length to be x and the width to be y.
Since the area is 64cm, hence
x*y = 64 (equation 1)
Since the perimeter is 40cm, hence
x + x + y + y = 40
2x + 2y = 40
2(x + y) = 2(20)
x + y = 20 (equation 2)
Hence by using simultaneous equation,
x = 20 - y (equation 3)
Substituting equation 3 into equation 1, we get
(20-y)*y=64
20y-y^2=64
Tidying up the equation,
y^2 - 20y + 64 = 0
By using factorisation,
(y-16)(y-4)=0
y=16 or y=4
By substituting y=16 into equation 1,
x*16=64
x = 4
By substituting y = 4 into equation 1,
x*4=64
x=16
Therefore,
The length is 4 cm while the width is 16 cm.
OR
The length is 16 cm while the width is 4cm.
Hope this helps!!
Answer:
B
Step-by-step explanation:
the first fish tank has 100 gallons of water and 1 gallon is removed every hour which makes 100-h
the second tank has 40 gallons in it and 2 gallons are added every hour which makes 40+2h
after 20 hours the second tank will have more gallons than the first tank
this means that 40+2h would be greater than 100-h since it's also asking you "After how many hours will the first tank have less water than the second?"
Answer:
Slope= -5
y-intercept=8
Step-by-step explanation:
In the formula y=mx+b
The m is the slope and the b is the y-intercept.
The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
The area of a parallelogram is:
A = b * h
Where,
b: base
h: height
Clearing the base we have:
b = A / h
Substituting values we have:
b = (6x2 + x + 3) / 3x
Rewriting we have:
b = 2x + 1 / x + 1/3
Answer:
the length of the base is:
b = 2x + 1 / x + 1/3
