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3 years ago

If 8 girls brought a lunch box and 6 boys didnt what is the probability of a student bringing one.

Mathematics

1 answer:

Tatiana [17]3 years ago

3 0

Answer:

43 percent

Step-by-step explanation:

6/14 ×100%

=0.248

=43%

first add up the total people, then substract the total of people to the people that didn't bring them, divide them then multiply it by 100%

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If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo

Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or, Q = 40 kg × 4200 × 18

or, Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0

3 years ago

What are the letters A7B × 3=C4D5

VMariaS [17]

A=4, B=5, C=1 and D=2 if you dont have more information of course.

8 0

3 years ago

Read 2 more answers

South Jeff Middle School is raising money for a local charity. Their goal is to raise $500 by their holiday break. If they have

xxTIMURxx [149]

They should earn 50$ each day because 50x100=500

6 0

2 years ago

A math problem has 25 questions.Some are worth 2 points and some are worth 3 points. The test is worth 60 points in total. Which

Margarita [4]

Answer:

There can be many possibilities

Possibilities:

one possibilities that is perfect according to me is:-

15questions of 2 points

15×2=30 points

10questions of 3 points

10×3=30 points

Total =30+30=60 points

Hope it helped you

lf not then I am sorry for this.

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8 0

2 years ago

Enter the number in standard notation.

Jobisdone [24]

<h3>The length in standard notation is 0.05 meter</h3>

Solution:

Given that,

Jeremy measured the length of an ant as $5 \times 10^{-2}\ meter$

We have to write the length in standard notation

From given,

$Length = 5 \times 10^{-2}\\\\Length = \frac{5}{10^{2}}\\\\Simplify\\\\Length = \frac{5}{100}\\\\Length = 0.05$

Thus the length in standard notation is 0.05 meter

Method 2:

$length = 5 \times 10^{-2}\ meter$

Use the exponent of 10 to determine how many places to move the decimal point

Since exponent is -2, is negative

Thus, we have to move the decimal point to right 2 places

$5 \times 10^{-2} = 0.05$

Thus the length in standard notation is 0.05 meter

5 0

3 years ago