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Phantasy [73]
3 years ago
6

Think About the Process The scale for the drawing of a rectangular

Mathematics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

The actual dimensions of the field are 28ft x 14ft. I dont know how I am supposed to mak an equation though.

Step-by-step explanation:

Hoped this somewhat helped.

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Please answerrrrrrrrrr​
Anna11 [10]
The answer is no (all you do it plug in the point that correspond with the x and y, in the equation
5 0
3 years ago
A) 10 - 3(2a + 3) + 4(a - 6)<br> Simplify
Veseljchak [2.6K]
2becaude 10a -3 =7 colonial
7 0
3 years ago
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Draw graphs of the following lines: The line through (-5, 2) having the slope of -3
Ivanshal [37]
What you want to do here is take this information and plug it into point-slope form. any time you're given a point and a slope, you generally want to plug it into this equation: y - y1 = m(x - x1).

in this equation, m is your slope and (x1, y1) is a given point. plug in your info--slope of -3 and (-5, 2).

y - 2 = -3(x + 5)

that is the equation of your line. however, if you want to graph it, this doesn't really make much sense to you. convert it to slope-intercept form, y = mx + b, by solving for y.

y - 2 = -3(x + 5) ... distribute -3
y - 2 = -3x - 15 ... add 2
y = -3x - 13 is your equation.

to graph this, and any other y = mx + b equation, you want to start with your y-intercept if it's present. your y intercept here is -13, which means the line you wasn't to graph crosses the y-axis at y = -13, or (0, -13). put a point there.

after you've plotted that point, you use your slope to graph more. remember that your slope is "rise over run"--you rise up/go down however many units, you run left/right however many units. if your slope is -3, you want to go down 3 units, then go to the right 1 unit. remember that whole numbers have a 1 beneath them as a fraction. -3/1 is your rise over 1.
6 0
3 years ago
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Find the midpoint of the segment with the given endpoints (5,-9) and (-2,-2)
QveST [7]
Another way to solve this is to use the Midpoint Formula.  The midpoint of a segment joining points (x_1,y_1) and (x_2,y_2) is

\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right)

So the midpoint of your segment is

\left(\frac{5+(-2)}{2},\frac{-9+(-2)}{2}\right) = \left(\frac{3}{2},-\frac{11}{2} \right)

Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points.  Ditto for the y-coordinate of the midpoint; just average the y's.
6 0
3 years ago
T5 ( volume of cylinder )
yan [13]

Answer:

Step-by-step explanation:

V=\pi r^2h=\pi *20^2*8 ≈ 10053.1in^3

4 0
3 years ago
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