Well (3-2^2)5 = -5
and 5-3^2=-4
5-2^2=1
2^2-5=-1
3^2-5=4
but if you have to multiply them by 5 as well then (2^2-5)5=-5
Here's what you need to know in order to answer this:
1 gallon = 128 fl oz
and
1 day = 24 hours.
Use those facts to invent fractions equal to ' 1 '.
Then use those to change the units of the "11 fl oz per hour".
You can multiply them ... since their value is ' 1 ', they won't
change the value of the "11 fl oz per hour", only the units.
(11 fl oz/hr) x (24 hr/da) x (1 gal / 128 fl oz)
= (11 x 24 x 1 / 128) (fl-oz - hr - gal) / (hr - da - fl-oz)
= 2.0625 gal/da
Answer:
5,868,000
Step-by-step explanation:
2,934,000 x 2 = 5,868,000
we have a maximum at t = 0, where the maximum is y = 30.
We have a minimum at t = -1 and t = 1, where the minimum is y = 20.
<h3>
How to find the maximums and minimums?</h3>
These are given by the zeros of the first derivation.
In this case, the function is:
w(t) = 10t^4 - 20t^2 + 30.
The first derivation is:
w'(t) = 4*10t^3 - 2*20t
w'(t) = 40t^3 - 40t
The zeros are:
0 = 40t^3 - 40t
We can rewrite this as:
0 = t*(40t^2 - 40)
So one zero is at t = 0, the other two are given by:
0 = 40t^2 - 40
40/40 = t^2
±√1 = ±1 = t
So we have 3 roots:
t = -1, 0, 1
We can just evaluate the function in these 3 values to see which ones are maximums and minimums.
w(-1) = 10*(-1)^4 - 20*(-1)^2 + 30 = 10 - 20 + 30 = 20
w(0) = 10*0^4 - 20*0^2 + 30 = 30
w(1) = 10*(1)^4 - 20*(1)^2 + 30 = 20
So we have a maximum at x = 0, where the maximum is y = 30.
We have a minimum at x = -1 and x = 1, where the minimum is y = 20.
If you want to learn more about maximization, you can read:
brainly.com/question/19819849
Answer:
9
Step-by-step explanation:
30 - (9+4 x 3)
30 - (9 + 12)
30 - 21
= 9
