<h3>
Answer: 95 degrees</h3>
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Explanation:
I recommend drawing it out to see what's going on. See the drawing below.
In the diagram, both angles are in the northeast corner of their four-corner configurations. They are both congruent corresponding angles. So that's why the second angle is also 95 degrees.
Side note: we could replace "northeast" with any of the other directions on the compass (such as southwest). All that matters is that they are in the same configuration.
Answer:
is D
Step-by-step explanation:
for egny
There are several different equations that can be used to find missing sides, these can be trigonometric functions or the distance formula. The trigonometric functions consist of sine (opposite/hypotenuse), cosine (adjacent/hypotenuse), and tangent (opposite/adjacent. The adjacent side is represented by the side next to the given angle measure, the opposite is the side that is connected to adjacent side and across from the given angle, and the hypotenuse is the diagonal that connects the opposite side to the given angle- most notable because its line isn't straight like the other sides.
The distance formula is used to find the measurement of missing side lengths in all quadrilaterals, and it's: D = sqrt(x2 - x1)^2 + (y2 - y1)^2 where x are the x-coordinates of two given points and y are the y-coordinates of the same two given points.
Step-by-step explanation:
a1 is the first term. In this case, 2.
r is the common ratio. Each term is multiplied by -3 to get the next term, so r = -3.
an = 2 (-3)ⁿ⁻¹
If you're using the app, try seeing this answer through your browser: brainly.com/question/2989024——————————
You have
y as an implicit function of
x:
sin(xy) – x = 0Use implicit differentiation. As
y is a function of
x, then you must apply the chain rule there:
d d—— [ sin(xy) – x ] = —— (0) dx dx d d d—— [ sin(xy) ] – —— (x) = —— (0) dx dx dx d—— [ sin(xy) ] – 1 = 0 dx d—— [ sin(xy) ] = 1 dx dcos(xy) · —— (xy) = 1 dxNow, apply the product rule for that last derivative:
![\mathsf{cos(xy)\cdot \left[\dfrac{d}{dx}(x)\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\ \mathsf{cos(xy)\cdot \left[1\cdot y+x\cdot \dfrac{dy}{dx}\right]=1}\\\\\\ \mathsf{y\,cos(xy)+x\,cos(xy)\cdot \dfrac{dy}{dx}=1}](https://tex.z-dn.net/?f=%5Cmathsf%7Bcos%28xy%29%5Ccdot%20%5Cleft%5B%5Cdfrac%7Bd%7D%7Bdx%7D%28x%29%5Ccdot%20y%2Bx%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%5Cright%5D%3D1%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7Bcos%28xy%29%5Ccdot%20%5Cleft%5B1%5Ccdot%20y%2Bx%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%5Cright%5D%3D1%7D%5C%5C%5C%5C%5C%5C%0A%5Cmathsf%7By%5C%2Ccos%28xy%29%2Bx%5C%2Ccos%28xy%29%5Ccdot%20%5Cdfrac%7Bdy%7D%7Bdx%7D%3D1%7D)
dyIsolate
—— :
dx dyx cos(xy) · —— = 1 – y cos(xy) dxAssuming
x cos(xy) ≠ 0,
dy 1 – y cos(xy)—— = ———————— <——— this is the answer.
dx x cos (xy)I hope this helps. =)
