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Semmy [17]
3 years ago
13

An open box with a square base should be constructed. the bottom, should be constructed from a heavy duty cardboard that cost $3

per square inches and the sides from a medium duty cardboard that cost $2 per square inches. if the volume of the box must be 120 cubic inches, what should be the dimensions of the box in order to minimize the cost for the material?
Mathematics
1 answer:
Lubov Fominskaja [6]3 years ago
4 0
I made several boxes with different sized square bases, such as 1x1, 2x2, 3x3, 4x4, 5x5, and 6x6. I calculated the heights of all of them, being 120, 30, 13.333, 7.5, 4.8, and 3.333 respectively. By using the $2/sq. in. for the sides and $3/sq. in. for the square base, I found that the box with the dimensions: 5x5x4.8 produced the most minimal cost at $267:

(5x4.8)x4 = 96 sq. in. x 2 = $192
5x5 = 25 sq. in. x 3 =$75

$192 + $75 = $267
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Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.
Dahasolnce [82]

<em>Note: you may have unintentionally missed to add the complete question. Therefore, after a little research, I am able to find the complete question which I am attaching to solve your query, which anyways would clear your concept. </em>

The complete Question:

Keenan gives Tisha half of his strawberries. Tisha keeps 4 of the strawberries she got from Keenan and gives the rest to Suvi.

a) Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Answer:

Part a)

An expression for the number of strawberries Tisha gives to Suvi will be:<em> </em>n=\frac{k}{2} -4

Part b)

Keenan could not have started with 6 strawberries

Step-by-step explanation:

Part a) <em>Write an expression for the number of strawberries Tisha gives to Suvi. Use k for the number of strawberries Keenan started with.</em>

Let k be the total number of strawberries which Keenan has.

So,

\frac{k}{2} is the number of strawberries Keenan gave to Tisha.

As Tisha keeps 4 strawberries and gives the rest to Suvi. Let n be the number of strawberries which Suvi has.

So,

n=\frac{k}{2} -4

\frac{k}{2}=n+4

k=2n+8

Therefore, an expression for the number of strawberries Tisha gives to Suvi will be:<em> </em>n=\frac{k}{2} -4

b) Could Keenan have started with 6 strawberries? Use your expression to explain why or why not.

Considering the expression for the number of strawberries Tisha gives to Suvi

n=\frac{k}{2} -4

Putting k = 6 in the expression

n=\frac{6}{2} -4

Solving the expression

n=3-4         ∵ \mathrm{Divide\:the\:numbers:}\:\frac{6}{2}=3

\mathrm{Subtract\:the\:numbers:}\:3-4=-1

n=-1

So, Keenan would have started with 6 strawberries, then Suvi would have -1 strawberries. Since, strawberries cannot be negative as Suvi cannot have negative number of strawberries.

Therefore, Keenan could not have started with 6 strawberries.

Keywords: word problem, expression

Learn more about word problem from brainly.com/question/3196729

#learnwithBrainly

3 0
3 years ago
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