A block of mass 2.60 kg is placed against a horizontal spring of constant k = 725 N/m and pushed so the spring compresses by 0.0
1 answer:
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Answer:
(a) 80.36 m/s^2
(b) 0.0933 second
Explanation:
initial velocity, u = 7.5 m/s
final velocity, v = 0 m/s
distance moved, s = 0.350 m
(a) Let a be the deceleration.
Use third equation of motion
a = 80.36 m/s^2
Thus, the deceleration is 80.36 m/s^2.
(b) Let the time taken is t
Use first equation of motion
v = u + a t
0 = 7.5 + 80.36 x t
t = 0.0933 second