Answer:
62.5 %
Explanation:
Let the initial intensity of unpolarized light is Io.
After first polariser the intensity of light becomes I'.
So, 
Now it passes through another polariser. The angle between the first polariser and the second polariser is given by Ф. The intensity is I''.
According to the law of Malus
Here, Ф = 30 degree
The percentage change in the intensity is given by
= 62.5 %
<span> static friction :) your very welcome
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Answer:
I know the first one is C.) 4J. I don't know of the answer for the second oneis suppose to be in N/m form? but I got
2,500N/m
Current is the amount of charged passed divided by elapsed time.
I = Q/Δt
I = current, Q = charge, Δt = elapsed time
We also know an electron has a charge of 1.6×10⁻¹⁹C, so let us find the total charge by multiplying this unit of charge by the total number of electrons:
Q = 1.6×10⁻¹⁹(3×10²⁰) = 48C
We also have Δt = 6s, so let's plug these values in to solve for I:
I = 48/6
I = 8A
Q = m.s.Δt
Δt = Q /m.s
Here, Q = 30,000 J
m = 390 g
s = 3.9 J/g C
Substitute their values,
= 30,000 / 390 *3.9
= 30,000 / 1521
= -20 C (approx.) [-ve sign 'cause temperature is decreasing ]
In short, Your Answer would be Option D
Hope this helps!
