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Tasya [4]
2 years ago
10

Factories completely 2x * (2x + 1) ^ 2 + (2x + 1)(4x ^ 2 - 3)

Mathematics
1 answer:
alexgriva [62]2 years ago
5 0

The <em>factored</em> form of the polynomial is (x - 0.556) · (x + 0.528 - i 0.242) · (x + 0.528 + i 0.242).

<h3>How to factor an algebraic equation</h3>

In this question we have an <em>algebraic</em> expression to be expanded by means of <em>algebraic</em> properties, the purpose of this handling is to modify the polynomial until its <em>standard</em> form is finally obtained and later we find its <em>factor</em> form by Cardano's method. Now we proceed to show the procedure in detail:

2 · x · (2 · x + 1)² + (2 · x + 1) · (4 · x² - 3)     Given

2 · x · (4 · x² + 4 · x + 1) + (2 · x + 1) · (4 · x²) + (2 · x + 1) · (- 3)      Perfect square trinomial/Distributive property

8 · x³ + 4 · x² + 2 · x + 8 · x³ + 4 · x² - 6 · x - 3     Distributive property/(- 1) · a = - a

16 · x³ + 8 · x² - 4 · x - 3     Distributive property/Definitions of addition and subtraction

(x - 0.556) · (x + 0.528 - i 0.242) · (x + 0.528 + i 0.242)      Cardano's method/Result

The <em>factored</em> form of the polynomial is (x - 0.556) · (x + 0.528 - i 0.242) · (x + 0.528 + i 0.242).

To learn more on polynomials: brainly.com/question/11536910

#SPJ1

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ella [17]

Answer:y=485

y=a(2)^t/d

a=150 d=13 t=22

Step-by-step explanation: y=150(2) 22/13

y=484.759843209

y=485

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Im a little rusty at this stuff Its been a long time.

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3 0
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Read 2 more answers
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dalvyx [7]
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