The <em>factored</em> form of the polynomial is (x - 0.556) · (x + 0.528 - i 0.242) · (x + 0.528 + i 0.242).
<h3>How to factor an algebraic equation</h3>
In this question we have an <em>algebraic</em> expression to be expanded by means of <em>algebraic</em> properties, the purpose of this handling is to modify the polynomial until its <em>standard</em> form is finally obtained and later we find its <em>factor</em> form by Cardano's method. Now we proceed to show the procedure in detail:
2 · x · (2 · x + 1)² + (2 · x + 1) · (4 · x² - 3) Given
2 · x · (4 · x² + 4 · x + 1) + (2 · x + 1) · (4 · x²) + (2 · x + 1) · (- 3) Perfect square trinomial/Distributive property
8 · x³ + 4 · x² + 2 · x + 8 · x³ + 4 · x² - 6 · x - 3 Distributive property/(- 1) · a = - a
16 · x³ + 8 · x² - 4 · x - 3 Distributive property/Definitions of addition and subtraction
(x - 0.556) · (x + 0.528 - i 0.242) · (x + 0.528 + i 0.242) Cardano's method/Result
The <em>factored</em> form of the polynomial is (x - 0.556) · (x + 0.528 - i 0.242) · (x + 0.528 + i 0.242).
To learn more on polynomials: brainly.com/question/11536910
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