<u>Answer:</u>
B. 
<u>Step-by-step explanation:</u>
• Now make x the subject of the equation:
• Replace x with f⁻¹(x) and y with x:
Answer:
f(g(-64)) = -190
Step-by-step explanation:
The functions are not well written.
Let us assume;
f(x) = x+1
g(x) = 3x+1
f(g(x)) = f(3x+1)
Replace x with 3x+1 in f(x)
f(g(x)) = (3x+1) + 1
f(g(x)) = 3x + 2
f(g(-64)) = 3(-64) + 2
f(g(-64)) = -192+2
f(g(-64)) = -190
<em>Note that the functions are assumed but same method can be employed when calculating composite functions</em>
3x - 2y = 1
2x + 2y = 4
Add the second equation to the first
5x = 5
2x + 2y = 4
Divide the first equation by 5
x = 1
2x + 2y = 4
Subtract the first equation from the second
x = 1
x + 2y = 3
Subtract the first equation from the second again
x = 1
2y = 2
Divide the second equation by 2
x = 1
y = 1
<h3>
So, the solution is x = 1 and y = 1 {or: (1, 1)} </h3>
Answer: 1
Step-by-step explanation: the probability mass function that defines a possion probability distribution is given below as
P(x=r) = e^-u × u^x/x!
For this question, x = 0 and u = 9.5
Hence we have that
P(x=0) = e^-0 × 9.5^0 / 0!
P(x=0) = 1 × 1/ 1 = 1
Answer:
$ 8,695.35
Step-by-step explanation:
This is a compound interest question
Amount after t years = A = P(1 + r/n)^nt
Where P = Initial Amount saved
r = interest rate
t = time in years
n = compounding frequency
A = 10,000
r = 3.5 %
t = 21 - 17 = 4 years
n = Compounded monthly = 12
Step 1
Converting R percent to r a decimal
r = R/100 = 3.5%/100 = 0.035 per year.
P = A / (1 + r/n)^nt
Solving our equation:
P = 10000 / ( 1 + (0.035/12)^12 ×4 =
P = $8,695.35
The principal investment required to get a total amount, principal plus interest, of $10,000.00 from interest compounded monthly at a rate of 3.5% per year for 4 years is $8,695.35.
