Solve for missing sides of a right triangle using the pythagorean theorem of 6 and 11 and x

Mathematics

2 answers:

sergiy2304 [10]3 years ago

8 0

The answer is 2.82842712475

Fantom [35]3 years ago

6 0

Each side has own formula, so which side is X

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1) If the polygon is regular, how do you find the measure of each exterior angle in the polygon?

NARA [144]

Divide 360 by the number of sides or angles that the polygon has

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2 years ago

What is the definition of mean???

Scilla [17]

Mean, in terms of math, is the total added values of all the data in a set divided by the number of data in the set. Make sense? If not, here' an example...

Let's say this is my data set:
1, 2, 5, 4, 3, 8, 7, 4, 6,10

To find the mean...
Step 1: Add all of them together.
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3 years ago

How does 0.03 compare to 0.003

kati45 [8]

0.03 compare to 0.003

While comparing decimals we write the decimals one below the other according to the place value of each digits in place value chart

ones -- point -- Tenths -- Hundredths -- Thousandths

0 . 0 3

0 . 0 0 3

Now we compare each digit left to right. We have 3 in hundredths and 0 in hundredths place. 3 is greater

So 0.03 is greater than 0.003

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6 0

3 years ago

Read 2 more answers

What is the vertex form of Y = x2 - 6x + 6?

ahrayia [7]

Answer:

$\large\boxed{y=(x-3)^2-3}$

Step-by-step explanation:

The vertex form of a quadratic equation y = ax² + bx + c:

y = a(x - h)² + k

(h, k) - coordinates of a vertex

We have the equation y = x² - 6x + 6.

Convert to the vertex form:

$y=x^2-2(x)(3)+6\\\\y=\underbrace{x^2-2(x)(3)+3^2}_{(*)}-3^2+6\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\qquad(*)\\\\y=(x-3)^2-9+6\\\\y=(x-3)^2-3\to h=3,\ k=-3$