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Firlakuza [10]
2 years ago
15

Can someone help me with these problems and show work please !

Mathematics
1 answer:
tester [92]2 years ago
3 0

The domain of g(x)= 3x^2 is Real number and it's range is {y∈R / y≥0}

The domain of h(x)= -3x^2 is Real number and it's range is {y∈R / y ≤0}

The domain of a function f(x) is the set of all values for which the function is defined, and the domain of a function is the set of all values that f takes on. The domain and range are defined for a relation and are the sets of all x-coordinates and all y-coordinates of ordered pairs.

The graph of f(x)= x^2 is given

We need to find the domain and range of g(x)=3x^2 and h(x)= -3x^2

The Graph of 3x^2 is different from x^2 in terms of plotting

When ,

x= -2 g(x)=12

x=-1 g(x)=3

x=0 g(x)=0

x=1 g(x)=3

x=2 g(x)=12

The Graph of -3x^2 is different from x^2 in terms of plotting

When ,

x= -2 g(x)=-12

x=-1 g(x)= -3

x=0 g(x)=0

x=1 g(x)= -3

x=2 g(x)=-12

Domain of g(x) is R and it's range is {y∈R / y≥0}

Domain of h(x) is R and it's range is {y∈R / y ≤0}

<u>Learn more about </u><u>domain and range</u><u> here:</u>

brainly.com/question/28100489

#SPJ1

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pantera1 [17]

Given:

The given terms are

4p^3mn^2 and 2pm^2n^3

To find:

The common factors of given terms.

Solution:

We have,

4p^3mn^2 and 2pm^2n^3

The factor forms are

4p^3mn^2=2\times 2\times p\times p\times p\times m\times n\times n

2pm^2n^3=2\times p\times m\times m\times n\times n\times n

The common factors are 2, p, m, n, n. So,

Common factors = 2\times p\times m\times n\times n

                            = 2pmn^2

Therefore, the common factor of given terms is 2pmn^2.

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Answer:

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