<u>SAS Criterion:</u> If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.
From the diagram you can see that:
<A ≅ <F ≅ <P
AB ≅ GF ≅ PQ
AC ≅ FE ≅ PR
This means that ΔABC, ΔFGE, and ΔPQR are congruent.
How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
Learn more about Density of the Neutron star here:brainly.com/question/15700804
Answer:
I put 7 but im not sure if it correct yet
Explanation:
if point U is on RS but the U to P is 7 units then U must be the midpoint of RS but i have no idea hope this helps
