Let n be the sum of all 6 numbers:
In the 1st case n/6 = 41 ==> n =246
in the 2nd case n'/5 = 46===> n' =230, the unknown number is n-n' =246-230
= 16
1 -- I
10 -- X
100 -- C
1000 -- M
The mean is the average of a set of numbers. So to do that:
add all the numbers 120+235+98+142=$595
Then divide that by the total number in the set, in this case it is 4.
$595/4= $148.75 assuming that the prices given are the final price of the job.
Answer:
(f+g)(x) = 60x + 400
Step-by-step explanation:
Given :
Amount in account A:
f(x) = 20x + 100
Amount in account B :
g(x) = 40x + 300
Total amount in Account A and B:
f(x) + g(x) = (20x + 100) + (40x + 300)
(f+g)(x) = (20x + 40x) + (100 + 300)
(f+g)(x) = 60x + 400