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1 year ago

how much would 500 invested at 4% interest compounded continuously be worth after 7 years? round your answer to the nearest cent

Mathematics

1 answer:

vladimir1956 [14]1 year ago

4 0

Answer: the answer is 661.55

Step-by-step explanation:

interest formula: F = Pe^(rt)

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What is the slope of (-4,6) and (2,-5)

Dominik [7]

Answer:

-11/6

Step-by-step explanation:

Slope can be found with this equation:

(y₁ - y₂) / (x₁ - x₂)

What this essentially tells us to do is to put one set of the x and y coordinates into x₁ and y₁, respectfully. Then, put the other set of x and y points as x₂ and y₂.

With this scenerio, we can substitute the given points into the formula.

(6 - (-5)) / (-4 - 2) =

(6 + 5 ) / (-6) =

11 / (-6) =

-11/6

The slope is - 11/6

4 0

3 years ago

Read 2 more answers

What is 9.39 to one decimal place

mafiozo [28]

9.4 because the number after the firs decimal point is higher than 5

5 0

3 years ago

-8x + 4 = 36 ggggggg

LekaFEV [45]

-8x+4=36
-4 -4
-8x=32
divde be -8 on both sides
x=-4

5 0

3 years ago

Please help with math

Shtirlitz [24]

1.) - sqrt. 2 (which, in decimal, is about -1.4142…) , 0, sqrt. 5 (which, in decimal, is about 2.2360…) , 13/4

2.) -1.5, 3/4 (which, in decimal, is 0.75) , 3, sqrt 10 (which, in decimal, is about 3.1622…)

3.) -3/2 (which, in decimal, is -1.5), -3/7 (which, in decimal, is about -0.4285…) , 0.75, 2

5 0

2 years ago

Express in Simper Fom : y-x

AveGali [126]

Simplify

$E=\dfrac{\frac{x}{y}-\frac{y}{x}}{\frac{1}{y}+\frac{1}{x}}$

Conditions for the existance of $E:$

$x\neq 0~~\text{ and}~~y\neq 0~~\text{ and }~~x\neq -y.$

(otherwise, the one of the denominators would be zero.)
____________________

Simplifying:

$E=\dfrac{\frac{x}{y}-\frac{y}{x}}{\frac{1}{y}+\frac{1}{x}}$

Multiply both the numerator and the denominator by $xy:$

$E=\dfrac{xy\cdot \left(\frac{x}{y}-\frac{y}{x} \right )}{xy\cdot \left(\frac{1}{y}+\frac{1}{x} \right )}\\\\\\ E=\dfrac{\frac{xy\cdot x}{y}-\frac{xy\cdot y}{x}}{\frac{xy}{y}+\frac{xy}{x}}\\\\\\ E=\dfrac{x^{2}-y^{2}}{x+y}\\\\\\ E=\dfrac{(x+y)(x-y)}{x+y}$

Simplify common factors:

$E=x-y\\\\\\ \therefore~~\boxed{\begin{array}{c}\dfrac{\frac{x}{y}-\frac{y}{x}}{\frac{1}{y}+\frac{1}{x}}=x-y \end{array}}$

6 0

3 years ago