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Bingel [31]
1 year ago
13

Which sequences are geometric? Select three options.

Mathematics
1 answer:
xenn [34]1 year ago
3 0

(i) –2.7, –9, –30, –100, ... case of a geometric sequence

(ii) –1, 2.5, –6.25, 15.625, ... case of a geometric sequence

(iii) 9.1, 9.2, 9.3, 9.4, ... not a case of a geometric sequence

(iv) 8, 0.8, 0.08, 0.008, ... case of a geometric sequence

(v) 4, –4, –12, –20, .. not a case of a geometric sequence

What is a geometric sequence?

A geometric sequence is one in which the ratio of two succeeding terms is fixed. The common ratio is what's known as this ratio.

Checking each sequence one by one right now.

(i) –2.7, –9, –30, –100, ...

r=(-9/2.7)=3.33

=(-30/9)=3.33

=(-100/9)=3.33

⇒This is a case of a geometric sequence

(ii) –1, 2.5, –6.25, 15.625, ...

r=(2.5/-1)=2.5

=(-6.25/2.5)=2.5

=(15.625/-6.25)= 2.5

⇒This is a case of a geometric sequence

(iii) 9.1, 9.2, 9.3, 9.4, ...

since the ratio between terms is not the same.

⇒This is not a case of a geometric sequence

(iv) 8, 0.8, 0.08, 0.008, ...

since the ratio between terms is the same.

⇒This is a case of a geometric sequence

(v) 4, –4, –12, –20, ..

since the ratio between terms is not the same.

⇒This is not a case of a geometric sequence

To learn more about geometric sequence visit:

brainly.com/question/24643676

#SPJ1

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Answer:

The correct option is (D).

Step-by-step explanation:

To construct the (1 - <em>α</em>)% confidence interval for population proportion the distribution of proportions must be approximated by the normal distribution.

A Normal approximation to binomial can be applied to approximate the distribution of proportion <em>p</em>, if the following conditions are satisfied:

  • n\hat p \geq 10
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In this case <em>p</em> is defined as the proportions of students who ride a bike to campus.

A sample of <em>n</em> = 125 students are selected. Of these 125 students <em>X</em> = 6 ride a bike to campus.

Compute the sample proportion as follows:

\hat p=\frac{X}{n}=\frac{6}{125}=0.048

Check whether the conditions of Normal approximation are satisfied:

n\hat p =125\times 0.048=610

Since n\hat p, the Normal approximation to Binomial cannot be applied.

Thus, the confidence interval cannot be used to estimate the proportion of all students who ride a bike to campus.

Thus, the correct option is (D).

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3 years ago
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3 years ago
Jessica is shopping for a new car. She found a blue car that has a 12-gallon gas tank and can go 384 miles on one tank. She foun
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Answer:

Silver car

Step-by-step explanation:

It seems pretty hard but it's actually REALLY easy. gas mileage means the number of miles you can go on a particular amount of gallons. But the gallons have to be the same for both cars so that it's fair.

so let's go with 10 gallons. pretty broad number right?

so to get 12 gallons(the gallons for the blue car) to 10, We divide it by 12 then multiply it by 10. Try it yourself, (12/12)*10=???

then we do that to 384 (the miles for the blue car)

(384/12)*10=320

so 320 is the mileage for the first car. Repeat the steps for the silver car!

(14/14)*10=10

so then: (504/14)*10= 360.

So which is bigger, 320 or 360?

360 is bigger, meaning it has better gas mileage.

5 0
3 years ago
arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)
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We have to rationalize the denominator:
\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\  \frac{-2}{ \sqrt{x+y-2} -  \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2})  }{x+y-2-(x+y+2)}= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2})  }{x+y-2-x-y-2}= \\  \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}  }{-4}= \\  \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2}  }{2}
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3 years ago
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Answer:

The height of the toy is 9 feet after 1 second

Step-by-step explanation:

we have

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where

h(t) is the toys height from the ground

t is the time in seconds

so

For t=1 sec

substitute the value of t in the quadratic equation and solve for h(t)

h(1)=-2(1)^2+7(1)+4

h(1)=9\ ft

3 0
3 years ago
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