Answer:
54.7 ft
Step-by-step explanation:
The question given above can be summarised in the attached photo.
u = Initial distance from the building
x = final distance from the building
y = distance moved from the initial point.
First, we shall determine the value of 'u'. This can be obtained as follow:
Opposite = 200 ft
Adjacent = u
Angle θ = 45°
Tan θ = Opposite / Adjacent
Tan 45 = 200 / u
Cross multiply
u × Tan 45 = 200
u × 1 = 200
u = 200 ft
Next, we shall determine the value of 'x'. This can be obtained as follow:
Opposite = 200 ft
Adjacent = x
Angle θ = 54°
Tan θ = Opposite / Adjacent
Tan 54 = 200 / x
Cross multiply
x × Tan 54 = 200
x × 1.3764 = 200
Divide both side by 1.3764
x = 200 / 1.3764
x = 145.3 ft
Finally, we shall determine the value of 'y'. This can be obtained as follow:
u = 200 ft
x = 145.3 ft
y =?
u = x + y
200 = 145.3 + y
Collect like terms
y = 200 – 145.3
y = 54.7 ft
Thus, the person walked 54.7 ft
The Maximum amount of minutes she could use would be 210
Formula:
0.05x + 25 <= 35.50
Predetermined overhead= total estimated overhead cost(machine hours , direct labor) /estimated allocation base
predetermined overhead= $534,000 +(31000 DLH x $3)
predetermined overhead= $20.23/DLH
hope this helps
Answer:
5/2
Step-by-step explanation:
The 5^-3 and 5^6 cancel out to be 5^3. Then the 5^3 cancels out with the 5^2 in the denominator and leaves you with just a 5. The 2^2 makes the 2^3 in the denominator just 2. So, you are left with 5/2! Hope this helps.
Answer:
r≈23.4cm
Step-by-step explanation: