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JulsSmile [24]
3 years ago
14

Kayla is pricing whole wheat flour.

Mathematics
1 answer:
lianna [129]3 years ago
5 0
A 2 pound pag at food saver sells flour for the lowest because if you buy the same amount of flour for each one easiest way would be 70 pounds and if you compare all four you will notice a 2 pound bag is the lowest unit price
5-90.3
2-87.5
7-94.5
10-90.23
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How does a compass and straightedge help you make a triangle
trasher [3.6K]

Answer:

A compass and straightedge allow for a more accurate rendition of a triangle, especially one needed to be specific measures

Step-by-step explanation:

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3 years ago
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A company purchased a machine for $970,000. the machine has a useful life of 12 years and a residual value of $4,500. it is esti
harina [27]
Cost less salvage value = 970,000 - 4500 = 965,500
Capacity of machine = 1,000,000 units.
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8 0
3 years ago
Is square root 1-cos^2theta=-sintheta true? if so, in which quadrants does angle theta terminate?
oksano4ka [1.4K]

Yes it is true:

(1 - cos^2 x) = sin^2 x Sqr.(1 - cos^2 x) = sin x and (-sinx) True, since sin x negative. Also, x terminates in quadrant 3 and 4. Hope this is helpful

4 0
2 years ago
There are (42)3 ⋅ 40 horses on a stud farm. What is the total number of horses on the farm?
Doss [256]

Answer:

5040

Step-by-step explanation:

When a number is in the Parenthesis that means you multiply. First you do 42*3 The answer would be 126. Since there is another Multiplication sign you just plug in your quotient (answer) into the problem. Now the equation is 126*40. 126*40=5040

6 0
2 years ago
Someone please be awesome and help me please :(
solong [7]

Answer:

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Step-by-step explanation:

x^2+\frac{b}{a}x+\frac{c}{a}=0

They wanted to complete the square so they took the thing in front of x and divided by 2 then squared.  Whatever you add in, you must take out.

x^2+\frac{b}{a}x+(\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

Now we are read to write that one part (the first three terms together) as a square:

(x+\frac{b}{2a})^2+\frac{c}{a}-(\frac{b}{2a})^2=0

I don't see this but what happens if we find a common denominator for those 2 terms after the square.  (b/2a)^2=b^2/4a^2 so we need to multiply that one fraction by 4a/4a.

(x+\frac{b}{2a})^2+\frac{4ac}{4a^2}-\frac{b^2}{4a^2}=0

They put it in ( )

(x+\frac{b}{2a})^2+(\frac{4ac}{4a^2}-\frac{b^2}{4a^2})=0

I'm going to go ahead and combine those fractions now:

(x+\frac{b}{2a})^2+(\frac{-b^2+4ac}{4a^2})=0

I'm going to factor out a -1 in the second term ( the one in the second ( ) ):

(x+\frac{b}{2a})^2-(\frac{b^2-4ac}{4a^2})=0

Now I'm going to add (b^2-4ac)/(4a^2) on both sides:

(x+\frac{b}{2a})^2=\frac{b^2-4ac}{4a^2}

I'm going to square root both sides to rid of the square on the x+b/(2a) part:

x+\frac{b}{2a}=\pm \sqrt{\frac{b^2-4ac}{4a^2}}

x+\frac{b}{2a}=\pm \frac{\sqrt{b^2-4ac}}{2a}

Now subtract b/(2a) on both sides:

x=\frac{-b}{2a} \pm \frac{\sqrt{b^2-4ac}}{2a}

Combine the fractions (they have the same denominator):

x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}

6 0
3 years ago
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