Question

What is the center of the circle given the following equation? (x-h)² + (y-k)² = r²​

Answer 1

It is the general equation of a circle

Correct answer:

The general equation of a circle is $(x - h)^2 + (y - k)^2 = r^2,$where (h, k) represents the location of the circle's center, and r represents the length of its radius. if we take some entities as $h=4,k=-3$ first has the equation of $(x - 4)^2 + (y + 3)^2 = 29$. This means that its center must be located at (4, –3), and its radius is √29.

Reference link -

What is the center of a circle whose equation is x2 + y2 + 4xhttps://brainly.in ›

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Answer 2

Answer:

on a coordinates plane :

The point of coordinates (h , k) is the center of the circle.

Step-by-step explanation:

by definition the expression:

(x-h)² + (y-k)² = r²

is the equation of the circle (in standard form)

Where r is the radius and (h , k) is the center of the circle.