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Simora [160]
2 years ago
15

Use the recursive formula to find the first five terms in the arithmetic sequence.

Mathematics
1 answer:
nasty-shy [4]2 years ago
6 0

Answer:

3, 1, - 1, - 3, - 5

Step-by-step explanation:

using the recursive formula and f(1) = 3 , then

f(2) = f(1) - 2 = 3 - 2 = 1

f(3) = f(2) - 2 = 1 - 2 = - 1

f(4) = f(3) - 2 = - 1 - 2 = - 3

f(5) = f(4) - 2 = - 3 - 2 = - 5

first 5 terms are 3, 1, - 1, - 3, - 5

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A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. Find the total area of the pyramid.
Tanzania [10]

The total area of pyramid is 113.569 square units

The equation to find the total area of the pyramid is Total area = base area + lateral area.

<u>Solution:</u>

Given, A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

<em><u>The total area of pyramid is given by:</u></em>

A=A_{b}+A_{l}   ---- eqn 1

Where,

A_{b} \text { is the base area and } A_{l} \text { is the lateral area }

<em><u>The area of base is given as:</u></em>

A_{b}=\frac{3 \sqrt{3}}{2} l^{2}

Where "l" is the side of hexagon.

Substituting we get,

\begin{array}{l}{A_{b}=\frac{3 \sqrt{3}}{2}(4)^{2}} \\\\ {=\frac{3 \sqrt{3}}{2} \times 16=3 \sqrt{3} \times 8} \\\\ {A_{b}=24 \sqrt{3}}\end{array}

<em><u>The lateral area is given as:</u></em>

A_{l}=3 b h

Where,

b: base of the triangle

h: height of the triangle

Substituting we get,

\begin{array}{l}{A_{l}=3 \times(4) \times(6)} \\\\ {A_{l}=72}\end{array}

Plugging in the values we found in eqn 1 we get,

A=24 \sqrt{3}+72

A = 113.569 square units

<em><u>Summarizing the results:</u></em>

The total area of pyramid is 113.569 square units approximately

The equation used to find total area of pyramid is Total area = base area + lateral area.

8 0
3 years ago
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