Question

The points R(3,−3), S(8,0), and T(4,1) are connected to form △RST.

Answer 1

Answer:

Isosceles.

Step-by-step explanation:

We are going to check it with the distance formula

d(R,T) = $\sqrt[2]{(3-4)^{2}+(-3-1)^{2}}$

= $\sqrt[2]{(-1)^{2}+(-4)^{2}}$

= $\sqrt[2]{1+16}$

=  $\sqrt[2]{17}$.

d(T,S) = $\sqrt[2]{(4-8)^{2}+(1-0)^{2}}$

= $\sqrt[2]{(-4)^{2}+(1)^{2}}$

= $\sqrt[2]{16+1}$

=  $\sqrt[2]{17}$.

d(S,R) = $\sqrt[2]{(8-3)^{2}+(0-(-3))^{2}}$

= $\sqrt[2]{(5)^{2}+(3)^{2}}$

= $\sqrt[2]{25+9}$

=  $\sqrt[2]{34}$.

Then, as the triangle has two sides with the same length, the triangle is isosceles.

Answer 2

right isosceles

rs:34&rs=rt+st

rt:17

st:17

ab=[(x(a)-x(b))+(y(a)+y(b))]