60%, 900/1500 would be .6 and in terms of percent would be 60.
The product a number with its square is equal to 8. Find the number.
Answer:
the number is 2
Step-by-step explanation:
Let us assume the number to x.
So, according to the equation:
![\textrm{x}\times\textrm{x}^{2}=8\\ \textrm{x}^{3}=8\\ \textrm{x}=\sqrt[3]{8}\\ \therefore \textrm{x}=2](https://tex.z-dn.net/?f=%5Ctextrm%7Bx%7D%5Ctimes%5Ctextrm%7Bx%7D%5E%7B2%7D%3D8%5C%5C%20%5Ctextrm%7Bx%7D%5E%7B3%7D%3D8%5C%5C%20%5Ctextrm%7Bx%7D%3D%5Csqrt%5B3%5D%7B8%7D%5C%5C%20%5Ctherefore%20%5Ctextrm%7Bx%7D%3D2)
To answer you need to isolate T so you add 19 to both sides. so T = 36
Hope that helped! If you don't get it message me and I can try to re explain :)
Answer:
679
Step-by-step explanation:
The goal of this exercise is to find a three digit number given five statements.
1 - We can conclude that two digits out of 964 are correct but in the wrong place.
2 - One digit out of 147 is correct, but in the wrong place
3 - One digit out of 189 is correct and in the right place. Since 1 is on the same place in 147 and 189, 1 is not the correct digit. The correct digit is either 8 or 9.
4 - One digit out of 286 is correct, but in the wrong place. Since 8 is on the same place in 189 and 286, 8 is not the correct digit. We can then conclude that 9 is correct (statement 3) and in the right place (third) and that either 2 or 6 are correct but in the wrong place.
5 - 523 are all wrong. We can then conclude that 6 is correct and that is not in the third or second place, which leaves it in the first place.
If 1 and 4 are incorrect, from the second statement, we infer that 7 is the remaining correct digit at the second place.
Therefore the number is 679
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