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koban [17]
2 years ago
7

2. Calculate the number of moles represented by the following masses.

Chemistry
1 answer:
aliina [53]2 years ago
3 0

a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

<h3>What is the molar mass?</h3>

The molar mass is the mass in grams of 1 mole of particles, that is, the mass in grams of 6.02 × 10²³ particles. The units are g/mol.

We want to calculate the number of moles represented by different masses of different substances. In each case, the conversion factor between mass and moles is the molar mass.

  • a. 2.00 × 10² g of silver (Ag)

The molar mass of silver is 107.87 g/mol.

2.00 × 10² g × (1 mol/107.87 g) = 1.85 mol

  • b. 37.1 g of silicon dioxide (SiO₂)

The molar mass of silicon dioxide is 60.08 g/mol.

37.1 g × (1 mol/60.08 g) = 0.618 mol

a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

Learn more about molar mass here: brainly.com/question/21334167

#SPJ1

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2 moles of carbon atoms ( 6.022 x 10^23 particles / mole  ) = 1.20 x10^24 particles
<span>
2 moles of carbon dioxide molecules </span>( 6.022 x 10^23 particles / mole  ) = 1.20 x10^24 particles<span>

2 moles of diatomic oxygen molecules </span>( 6.022 x 10^23 particles / mole  ) = 1.20 x10^24 particles

As you can see, no matter what is the gas as long as they have the same number of moles, they would also have same number of particles<span />
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How many grams are in 3.01 x 1024 molecules of H2SO4
tresset_1 [31]

Answer:

490. g H₂SO₄

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

3.01 × 10²⁴ molecules H₂SO₄

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂SO₄ - 2(1.01) + 32.07 + 4(16.00) = 98.09 g/mol

<u>Step 3: Convert</u>

<u />3.01 \cdot 10^{24} \ molecules \ H_2SO_4(\frac{1 \ mol \ H_2SO_4}{6.022 \cdot 10^{23} \ molecules \ H_2SO_4} )(\frac{98.09 \ g \ H_2SO_4}{1 \ mol \ H_2SO_4} ) = 490.287 g H₂SO₄

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

490.287 g H₂SO₄ ≈ 490. g H₂SO₄

6 0
3 years ago
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