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koban [17]
2 years ago
7

2. Calculate the number of moles represented by the following masses.

Chemistry
1 answer:
aliina [53]2 years ago
3 0

a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

<h3>What is the molar mass?</h3>

The molar mass is the mass in grams of 1 mole of particles, that is, the mass in grams of 6.02 × 10²³ particles. The units are g/mol.

We want to calculate the number of moles represented by different masses of different substances. In each case, the conversion factor between mass and moles is the molar mass.

  • a. 2.00 × 10² g of silver (Ag)

The molar mass of silver is 107.87 g/mol.

2.00 × 10² g × (1 mol/107.87 g) = 1.85 mol

  • b. 37.1 g of silicon dioxide (SiO₂)

The molar mass of silicon dioxide is 60.08 g/mol.

37.1 g × (1 mol/60.08 g) = 0.618 mol

a. There are 1.85 moles in 2.00 × 10² g of silver (Ag).

b. There are 0.618 moles in 37.1 g of silicon dioxide (SiO₂)

Learn more about molar mass here: brainly.com/question/21334167

#SPJ1

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Answer: There are 0.000043 moles of melatonin.

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

given mass = 10 mg = 0.01 g

molar mass of C_{13}H_{16}N_2O_2 = 232.28 g

{\text {moles of melatonin}}=\frac{0.01g}{232.28g/mol}=0.000043moles

Thus there are 0.000043 moles of melatonin

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Describe the method of steel manufacture used when removes the impurities carbon, phosphorus and sulfur​
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Explanation:

Steelmaking is the process of producing steel from iron ore and/or scrap. In steelmaking, impurities such as nitrogen, silicon, phosphorus, sulfur and excess carbon (most important impurity) are removed from the sourced iron, and alloying elements such as manganese, nickel, chromium, carbon and vanadium are added to produce different grades of steel.

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Addie mixes together a solution of 10 grams of
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= 150 gram

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Determine the number of atoms of each element in the empirical formula of a compound with the following composition:
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To determine the empirical formula of the compound, we assume a basis of 100 g of this compound. We calculate as follows:

C = 68.75 g
H = 10.90 g
O = 20.35 g

We convert these mass to moles,
C = 68.75 g / 12.01 g/mol = 5.72 mol
H = 10.90 g / 1.01 g/mol = 10.79 mol
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C = 5.72 mol / 1.27 mol = 5
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O = 1.27 mol / 1.27 mol = 1

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3 years ago
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