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mixas84 [53]
3 years ago
8

What is oxidized and what is reduced in this reaction?

Chemistry
1 answer:
sineoko [7]3 years ago
6 0
N⁻²2H4(l) + 2H2O⁻¹2(l) → N⁰2(g) + 4H2O⁻²(g)

N is oxidized and O is reduced

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HI(aq)+NaOH(aq)→ <br> what the final balanced chemical equation with the phases included
julia-pushkina [17]

Answer:

HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)

Explanation:

Hello there!

In this case, for this neutralization reaction, it is possible to realize that one the neutralization products is water (pH=7) and the other one is the salt coming up from the cation of the NaOH and the anion of the HI:

HI(aq)+NaOH(aq)\rightarrow NaI+H_2O

Moreover, since the solubility of NaI is large in water, we infer it remains aqueous whereas the water is maintained as liquid:

HI(aq)+NaOH(aq)\rightarrow NaI(aq)+H_2O(l)

Which is also balanced as the number of atoms of all the elements is the same at both sides.

Best regards!

7 0
3 years ago
Surface tension ________________________.
Alex73 [517]
C) is higher for nonpolar substances than for polar ones

6 0
3 years ago
Atoms of the same element can have different forms; for example, carbon-12 and carbon-14.
cricket20 [7]
A carbon-12 atom has 6 protons (6P) and 6 neutrons (6N). But some types of carbon have more than six neutrons. We call forms of elements that have a different number of neutrons, isotopes. For example, carbon-14 is a radioactive isotope of carbon that has six protons and eight neutrons in its nucleus.
Hope that helps
5 0
3 years ago
PLS HELP The average atomic mass of carbon is 12.01 amu. Based on the atomic
Masteriza [31]

Answer:

B. There is a very large percentage of C-12.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize that, since the average atomic mass is 12.01 amu, then the C-12, with an atomic mass of 12.000 am prevails over C-13 with an atomic mass of 13.003 amu as long as the average is nearer to the former.

In such a way, the answer will be B. There is a very large percentage of C-12.

Regards!

7 0
3 years ago
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