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2 years ago

What happens to the appearance of an object as it gets hotter?

Physics

1 answer:

Marysya12 [62]2 years ago

5 0

Answer:

d) the object gets bluer

blue wavelengths are shorter than red wavelengths (in the visible spectrum)

blue light will carry more energy than an equivalent amount of red light

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What is the maximum wavelength of incident light that can produce photoelectrons from silver? The work function for silver is Φ=

zalisa [80]

Answer:

4.24nm

0.385eV

Explanation:

Maximum wavelength (λmax) :

λmax = ( hc) /Φ

h = plancks constant = 6.63 * 10^-34

c = speed of light = 3*10^8

1ev = 1.6 * 10^-19

Φ = 2.93eV = 2.93* (1.6*10^-19) = 4.688*10^-19

λmax = [(6.63 * 10^-34) * (3 * 10^8)] / 4.688*10^-19

λmax = 19.89 * 10^-26 / 4.688*10^-19

λmax = 4.242 * 10^-7 m

λmax= 4.24nm

B.)

E = hc / eλ eV

λ = 3.75nm = 3.75 * 10^-7m = 375 *10^-9

E = (6.63 * 10^-34) * (3 * 10^8) / (1.6 * 10^-19) * (375 * 10^-9)

E = 19.89 * 10^-26 / 600 * 10^-28

E = 0.03315 * 10^-26 + 28

E = 0.03315 * 10^2

E = 3.315 eV

Stopping potential : (3.315 eV - 2.93eV) = 0.385eV

7 0

3 years ago

Find the gravitational force that Earth (mass = 5.97 × 10²⁴ kg) exerts on the moon (mass = 7.35 × 10²² kg) when the distance bet

alexandr402 [8]

Explanation:

mass of earth (m1)=5.97×10^24

mass of moon (m2)=7.35×10^22

distance between their center (d)= 3.84×10^8

G=6.67×10^-11

now,

gravitational force =(F)= G(m1×m2)/d²

6.67×10^-11(5.97×10^24×7.35×10^22)/(3.84×10^8)
19.84×10^19

<h3>stay safe healthy and happy...</h3>

3 0

3 years ago

What is the change in internal energy if 20 J of heat is released from a system and the system does 50 J of work on the surround

hjlf

The correct answer is a -80 J

3 0

3 years ago

Read 2 more answers

As you know, a common example of a harmonic oscillator is a mass attached to a spring. In this problem, we will consider a horiz

Eddi Din [679]

a)E= U + K = $\frac{1}{2}$ kx² + $\frac{1}{2}$ mv²

The total energy of the system at any point in the motion is equal to the sum of the elastic potential energy of the spring, U, and of the kinetic energy of the mass, K:

E= U + K = $\frac{1}{2}$ kx² + $\frac{1}{2}$ mv²

where

'k' represents the spring constant

'x' is the compression/stretching of the spring with respect to its equilibrium position

'm' is the mass of the block attached to the spring

and 'v' is the speed of the block

b) <em>A=</em> $\sqrt{\frac{2E}{k}}$ <em> </em>

The amplitude of the motion compares to the most extreme displacement of the mass-spring system. The displacement of the system, x(t), at time t, for a simple harmonic oscillator is given by,

x= Asin(ωt+∅)

where

amplitude is 'A'

$\omega=\sqrt{\frac{k}{m}}$ is the angular frequency of the motion

t is the time

$\phi$ is the phase (we can take $\phi$ =0 )

The amplitude of the motion occurs when the displacement of the motion is maximum: x=A. Regarding energy, the mass-spring system is at its maximum displacement (x=A) when all the mechanical energy of the framework is elastic potential energy, so when the kinetic energy is zero:

K= $\frac{1}{2}mv^2$ =0

E= $\frac{1}{2}kA^2\\$ -->(1)

c) $v_{max}=\omega A$ <u></u>

When the elastic potential energy is zero, the maximum speed of the system occurs i.e U=0 and the kinetic energy is maximum, so:

U=0

E= $\frac{1}{2}mv_{max}^2$

According to the law of conservation of the mechanical energy, this energy must be equal to the energy of the system at its maximum displacement (1), so we can write

$\frac{1}{2}kA^2=\frac{1}{2}mv_{max}^2$