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3 years ago

A car has a force of 2000N and a mass of 1000kg. What is the acceleration of the car?

Physics

1 answer:

yan [13]3 years ago

5 0

Answer:

100

Explanation:

by dividing 2000N and 1000kg.

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When titanium bonds with oxygen, the ionic compound that forms has the chemical formula Ti2O3 and consists of Ti3+ ions and O2-

Lesechka [4]

hi!

just use cross method

7 0

3 years ago

A long-distance runner is running at a constant speed of 5 m/s.

vivado [14]

Answer:

3.33 minutes (3 minutes and 20 seconds)

Explanation:

Speed of the runner = s = 5 m/s

We need to calculate how will it take for runner to complete 1 km. We have the speed, the distance and we need to find the time. Before performing any calculations, we must convert the values to same units.

Speed is in m/s and distance is in kilometers. So we have to either convert speed to km/s or distance into meters. In this case, converting distance into meters would be a convenient option.

1 kilo meters = 1000 meters

The distance, speed and time are related by the equation:

Distance = Speed x Time

So,

Time = Distance/Speed

Using the values, we get:

t = 1000/5

t = 200 seconds

This means, the runner can complete 1 kilometers in 200 seconds. Since, there are 60 seconds in a minute, we can convert this time to minutes, by dividing it by 60. i.e.

$200 \text{ sec} = \frac{200}{60} \text{ min} = 3.33 \text{ min}$

Thus, it will take the runner 3.33 minutes (3 minutes and 20 seconds) to travel 1 km.

3 0

3 years ago

An athlete swims the length of 50m pool in 20sec, and

IRISSAK [1]

Answer:

1. 2.5 m/s

2. 2.27 m/s

3. 2.38 m/s

Explanation:

easy pz

3 0

3 years ago

Microwelds are formed where

Jlenok [28]

Between the bumps and dips of two surfaces. SO the answer is 2 surfaces. Hope this helps! :)

8 0

3 years ago

Read 2 more answers

Consider a long cylindrical charge distribution of radius R with a uniform charge density rho. Find the electric field at distan

ahrayia [7]

Answer: Ok, first lest see out problem.

It says it's a Long cylindrical charge distribution, So you can ignore the border effects on the ends of the cylinder.

Also by the gauss law we know that E¨*2*pi*r*L = Q/ε0

where Q is the total charge inside our gaussian surface, that will be a cylinder of radius r and heaight L.

So Q= rho*volume= pi*r*r*L*rho

so replacing : E = (1/2)*r*rho/ε0

you may ask, ¿why dont use R on the solution?

since you are calculating the field inside the cylinder, and the charge density is uniform inside of it, you don't see the charge that is outside, and in your calculation actuali doesn't matter how much charge is outside your gaussian surface, so R does not have an effect on the calculation.

R would matter if in the problem they give you the total charge of the cylinder, so when you only have the charge of a smaller r radius cylinder, you will have a relation between r and R that describes how much charge density you are enclosing.

3 0

3 years ago