Question

How far apart would you have to place the poles of a 1. 5 v battery to achieve the same electric field?

Answer 1

To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m

The potential difference is related to the electric field by:

∆V=Ed

where,

∆V is the potential difference

E is the electric field

d is the distance

what is potential difference?

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.

We want to know the distance the detectors have to be placed in order to achieve an electric field of

E=1v/cm=100v/cm

when connected to a battery with potential difference

∆v=1.5v

Solving the equation,we find

$d = \frac{ \:Δv}{e}$

$= \frac{1.5v}{100v/m}$

$= 1.5 \times 10 {}^{ - 2} m$

learn more about potential difference from here: brainly.com/question/28166044

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