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loris [4]
3 years ago
14

Which statement is true about two isotopes of the same element?

Physics
2 answers:
jarptica [38.1K]3 years ago
8 0

Answer:

D-They have different number of neutrons

Explanation:

brainliest? Plz

scZoUnD [109]3 years ago
3 0

Answer:

atoms that have the same # of protons but a DIFFERENT # of NEUTRONS

Explanation:

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Why are the plates in a capacitor parallel to each other?
TiliK225 [7]
To have a uniform field. The field is the voltage between the plates divided by the distance between the plates. If the distance varies so would the field between them.
6 0
3 years ago
Read 2 more answers
How do you relate and explain a planet's distance from the Sun to things like the time of their year & their average tempare
anzhelika [568]
What we call a "year" is the time a body takes to complete one orbital revolution
in its path around the sun.  The way gravity works, the farther a planet is from the
sun, the slower it moves, and the longer it takes to complete that trip.  So, farther
out from the sun means a longer "year".

Everybody knows that if you want to get more warmth, then you have to stand closer
to the fire, and it's the same with planets.  The farther a planet is from the sun, the less
heat it gets from the sun, and in most cases, that means its average temperature is
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The farther a planet's rotation axis is tilted from being perpendicular to the plane
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5 0
3 years ago
What is the frequency, in hertz, of a sound wave (v = 340 m/s) with a wavelength of 68 m?
hram777 [196]

Answer:

frequency = 5 Hz

Explanation:

F = v/wavelength

F = 340/68 =5Hz

5 0
2 years ago
It takes Venus 225 days to orbit the sun. If the Earth-sun distance is 1.5 × 10^11 m, what
loris [4]

Answer:

Distance between Venus and Sun is 1.0864x10^11 m

Explanation:

Data

T1 (Total time taken by earth to rotate around sun)=365 days

T2 (Total time taken by venus to rotate around sun)=225 days

R1 (Radius b/w Sun and earth)=1.5x10^11m

R2(Distance between Venus and Sun)=?

Solution

Apply Kepler Law

(R2)^3/(R1)^3=(T1)^2/(T2)^2

(R2)^3/(1.5x10^11)^3=(225^2)/(365^2)

R2=1.0864x10^11m

6 0
3 years ago
A 2.0 m conductor is formed into a square and placed in the horizontal xy-plane. A magnetic field is oriented 30.0° above the ho
Gnesinka [82]

Answer:

\phi_B = 0.216 T m^2

Explanation:

As we know that the length of the conductor is given as

L = 2 m

now if it is converted into a square then we have

L = 4a

a = \frac{L}{4} = 0.5 m

now the are of the loop will be

A = a^2 = 0.5(0.5) = 0.25 m^2

now the magnetic flux is defined as

\phi_B = BAcos\theta

here we know

B = 1.0 T

\theta = 30.0^o

\phi_B = (1.0 T)(0.25 m^2)(cos30)

\phi_B = 0.216 T m^2

5 0
2 years ago
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