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nata0808 [166]
2 years ago
8

There are 5 different families of triplets at a triplets convention. Each triplet shook hands with all the other triplets, excep

t his or her siblings. How many handshakes took place?
Mathematics
1 answer:
Verizon [17]2 years ago
5 0

There is a total of 90 handshakes.

<h3>How many handshakes took place?</h3>

There are 5 sets of triplets.

If we select one of the sets, each of the triplets will have one handshake with the other 12 people. So we have 36 handshakes at this point.

Now we only care for the other 4 sets.

We select one set again, each triple on that set will have one handshake with the other 9 people, so for the 3 triplets, we have a total of 27 new handshakes.

For the remaining 3 sets we do the same, this time we add 18 handshakes.

Finally, there are 2 sets of triplets, this time we add 9 new handshakes.

To get the total number of handshakes we need to add them all:

36 + 27 + 18 + 9 = 90

There is a total of 90 handshakes.

If you want to learn more about additions:

brainly.com/question/25421984

#SPJ1

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If you swim diagonally across the rectangular pool, the distance you swim is 10 meters.

<u>Given the following data:</u>

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To determine the distance you swim in meters, we would apply Pythagorean's theorem since the width is along the x-axis while the length is along the y-axis.

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Mathematically, Pythagorean's theorem is given by the formula:

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Substituting the given parameters into the formula, we have;

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Read more here: brainly.com/question/18890335

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