I believe the answer you're looking for is cellular respiration.
Answer:
First, we take the owl out, the total number of mouse increases at a higher rate and the chipmunks are also decreasing in numbers. In an ideal ecosystem, both mice (lets call it "a") and chipmunks (lets call it "b") should increase since the restraining factor has been removed. But that is the opposite of what we should see. In that case, we will take the owl to be the "limiting factor" for the rodents.
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The rodents will have free movement and exercise their fitness over the area, competition sets in between the two species. So we see, a flourishes while b dies out. This can be viewed most predictably that a has an overall greater fitness and would easily get resources and strive readily, which influences the survival rate for 2.
Hope you got something in any realm of understanding?
Answer:
These are some examples of hypertonic solutions: D10W (dextrose 10% in water), D5NS (dextrose 5% in . 9% sodium chloride), D5 12 NS (dextrose 5% in . 45% sodium chloride), and D5LR (dextrose 5% in lactated ringer).
Answer:
The correct answer is C. NADP⁺
Explanation:
NADP+ is the coenzyme that acts as the electron carrier during the photosynthetic process. The electron that is released from the splitting of water pass through the electron transport chain and at the end of the chain the electron is received by an electron carrier called NADP+.
So this passing of electron causes the transport of H ions in the thylakoid lumen from the stroma and when these ions come back through ATP synthase it forms ATP. Then these NADPH and ATP are used in the Calvin cycle to fix the CO2 into complex form. Therefore the correct answer is C. NADP⁺.
Answer:cuboidal epithelial cell
Explanation:as it is wide as they are tall,are cubed shaped they are usually found in lining glands where they secret substance
