Question

Find the equation of a circle with center at (5, 6) and radius 8.

Answer 1

Answer:

$(x-5)^2+(y-6)^2=64$

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

where:

• center = (a, b)
• radius = r

Given:

• center = (5, 6)
• radius = 8 units

Substitute the given values into the formula:

$\implies (x-5)^2+(y-6)^2=8^2$

$\implies (x-5)^2+(y-6)^2=64$

Therefore, the equation of a circle with the given values is:

$(x-5)^2+(y-6)^2=64$

Learn more about equations of circles at:

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Answer 2

Answer:

(x - 5)^2 + (y - 6)^2 = 64

Step-by-step explanation:

Every circumference is in the form:

(x - xc)^2 + (y - yc)^2 = r^2

Where xc is the x of the center. Yc is the y of the center. r is the radius. We just plug in the values and we're done.