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IrinaK [193]
2 years ago
13

The following two points are on a line: (2,3), (-2,5). What is the slope of the line?

Mathematics
1 answer:
8_murik_8 [283]2 years ago
8 0

Answer:

D

Step-by-step explanation:

slope = rise / run

slope = (5 - 3) / (-2 - 2)

slope = 2 / -4

slope = -2 / 4

slope = -1/2

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During the school year or each student planted 2 * 10^2 trees as part of a community service project. If there are 3.5 * 10^3 st
Nookie1986 [14]

Total 7*10^5 trees were planted.

Further explanation:

The product of both quantities will give us the total number of trees planted by the students for the community project.

So,

Given

Trees\ planted\ by\ each\ student=2*10^2\\Total\ students\ in\ school=3.5*10^3\\Total\ trees\ planted= (2*10^2)*(3.5*10^3)\\= 7*10^5\ trees

So, total 7*10^5 trees were planted.

Keywords: Product, exponents

Learn more about product and exponents at:

  • brainly.com/question/10081622
  • brainly.com/question/10341324

#LearnwithBrainly

4 0
3 years ago
Z+z+z for x=2, y=-3 , z=-4
REY [17]

Answer:

-12

Step-by-step explanation:

Just sustitute the z for -4

z+z+z

-4+(-4)+(-4)

=-12

I hope this help :)

5 0
3 years ago
Read 2 more answers
The graphs of functions f(x) and g(x) = f(x) + k are shown below:
Nataly [62]
Here's the info for f(x):  We are going to find the slope of the line and then write the equation for the line using one of the given points.  The coordinate points we are given are (0, 0) and (2, 4).  Using the slope formula:
m= \frac{y_{2} - y_{1} }{ x_{2}- x_{1}  }
gives us a slope equation of:
m= \frac{4-0}{2-0} and the slope is 2.  Using the point (0, 0) to write the equation of the line for f(x) looks like this in the slope-intercept form of the equation:
y- y_{1} =m(x- x_{1}) where m is the sloppe of 2 that we found and y_{1}  and  x_{1}  are the coordinates of one of the points.  It doesn't matter which one you choose; you will get the same answer whether you use (0, 0) or (2, 4): y-0=2(x-0)   Distributing that 2 into the parenthesis and simplifying gives you the equation of y = 2x, or in our function notation, f(x) = 2x.  Since f(x) is the first part of g(x), so far for g(x) we have that g(x) = 2x + k.  Now we will do the same thing for g(x) that we did for f(x) as far as writing its equation down; we don't need to find the slope cuz the slope of g(x) is the function f(x).  The equation for g(x), using the point (0, 2) (again, you could have used either point; I just picked (0, 2) cuz the other one has a decimal in it!): y - 2 = 2(x - 0).  Distributing that 2 into the parenthesis gives you this: y - 2 = 2x - 0; y = 2x + 2.  So 2 is your k value!

7 0
3 years ago
Read 2 more answers
Csc2theta=csctheta/2costheta<br><br>Can you help verify the identity
Yakvenalex [24]

csc(2x) = csc(x)/(2cos(x))

1/(sin(2x)) = csc(x)/(2cos(x))

1/(2*sin(x)*cos(x)) = csc(x)/(2cos(x))

(1/sin(x))*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)*1/(2*cos(x)) = csc(x)/(2cos(x))

csc(x)/(2*cos(x)) = csc(x)/(2cos(x))

The identity is confirmed. Notice how I only altered the left hand side (LHS) keeping the right hand side (RHS) the same each time.

7 0
3 years ago
Polygon ABCD is a rectangle what is the area
Andre45 [30]

Solution:

As, You have Written Polygon ABCD is a rectangle.

It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).

Join any of the diagonal of Rectangle either AC or B D.

In Right Δ ABC , Right angled at B

{\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AB \times BC---(1)

In Right  Δ ADC  , Right angled at D      

{\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AD \times DC---(2)

Adding (1) and (2) that is LHS to LHS and RHS to RHS

Ar( Δ ABC) +Ar( Δ ADC)=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC

So, Area of Rectangle= Product of any two Adjacent Sides

7 0
4 years ago
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