Y + 4 = 4/3(x + 1)...first we distribute
y + 4 = 4/3x + 4/3 ...now we subtract 4 from both sides
y = 4/3x + 4/3 - 4
y = 4/3x + 4/3 - 12/3
y = 4/3x - 8/3 <======
u will have a slope of 4/3....and a y int of (0,-8/3)...ur x int is (2,0)
in standard form, it is :
y = 4/3x - 8/3
-4/3x + y = -8/3
4x - 3y = 8....in case u need to find some points to graph
A=18
Explanation:multiply both sides by 3 to get rid of the fraction so u are left with a=18
We have been given an equation of circle 
. We are asked to find the center and radius of the circle.
First of all, we will write equation of circle is standard form 
, where center of circle is at point (h,k) and radius is r.
Let us complete the square for both x and y.
Adding half the square of coefficient of x and y term, we will get:
Therefore, the center of the circle is 
and radius is 4 units.
Answer:
x=59deg
Step-by-step explanation:
We will use tangent to find the angle because we do not know the length of the hypotenuse.
Tan(x)=opp/adj
Tan(x)=30/18
Tan(x)~59
So the last option is correct. 59deg
Answer:
256−1
Step-by-step explanation:
