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marysya [2.9K]
3 years ago
11

Anyone know the answer ?

Mathematics
1 answer:
notka56 [123]3 years ago
5 0

Answer:

3/4

Step-by-step explanation:

sin = opposite/hypotenuse

one side is 3, hypotenuse side is 5.

using the pythagorean theorem, we know that the third side is 4.

tan = opposite/adjacent

tanθ = 3/4

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(-6x+3)+(5x-4)<br><br> If you in the 7th grade or up you can answer this question
Otrada [13]

Answer:

-1x + -1

Step-by-step explanation:

(-6x+3)+(5x-4)

(-6x+3)+(5x-4)

-1x + -1

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3 years ago
HELP PLEASE! Write a quadratic function that passes through the point (-1,9), has an axis of symmetry of x=-3 and a minimum valu
xxTIMURxx [149]

Answer:

y = \frac{1}{2}x^{2} - 3x + 11.5

Step-by-step explanation:

Vertex form of a quadratic equation;

y = a( x - h )^{2} + k

Vertex of the parabolas (h, k)

The vertex of the parabola is either the minimum or maximum of the parabola. The axis of symmetry goes through the x-coordinate of the vertex, hence h = -3. The minimum of the parabola is the y-coordinate of the vertex, so k= 7. Now substitute it into the formula;

y = a ( x + 3 ) ^{2} + 7

Now substitute in the given point; ( -1, 9) and solve for a;

9 = a( (-1 ) + 3)^2 + 7\\9 = a (2)^{2} + 7\\9 = 4a + 7\\-7           -7\\2 = 4a\\\frac{1}{2} = a\\

Hence the equation in vertex form is;

y = \frac{1}{2}(x - 3)^{2} + 7

In standard form it is;

y = \frac{1}{2}x^{2} - 3x + 11.5

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3 years ago
Which pair of angles in the correct category to indicate whether the pair of angles is pair of vertical angles, a pair of line a
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We’re is the picture
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3 years ago
determine the equation of the circle if its center is (8,-6) and which passes through the points (5,-2).
ser-zykov [4K]

Answer:

(x - 8)² + (y + 6)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Here (h, k ) = (8, - 6 ) , then

(x - 8)² + (y - (- 6))² = r² , that is

(x - 8)² + (y + 6)² = r²

The radius is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (8, - 6 ) and (x₂, y₂ ) = (5, - 2 )

r = \sqrt{(5-8)^2+(-2-(-6))^2}

  = \sqrt{(-3)^2+(-2+6)^2}

  = \sqrt{9+4^2}

  = \sqrt{9+16}

   = \sqrt{25}

   = 5

Then equation of circle is

(x - 8)² + (y + 6)² = 5² , that is

(x - 8)² + (y + 6)² = 25

6 0
2 years ago
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