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3 years ago

PLEASE HELP! Slope parallel to line y = 2x/3 + 4 PLZ!

Mathematics

1 answer:

marta [7]3 years ago

5 0

Answer:

2/3

Step-by-step explanation:

I think you meant y=2/3x+4 because what you wrote is not the right way to right that equation, but anyways the slope of the parallel line is 2/3 because lines that are parallel have the same slope.

I hope this helps!

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ok. We are given the following equation:

$ph=-\log (H)$

Where:

$\begin{gathered} P=\text{ alkalinity} \\ H=\text{ hydrogen ion concentration} \end{gathered}$

Since we are asked to determine "H" we will solve for "H" in the equation. To do that we will first multiply both sides by -1:

$-ph=\log (H)$

Now, we will use the following property of logarithms:

$\log _aB=c\rightarrow B=a^c$

Applying the property and having into account that:

$\log (H)=\log _{10}(H)$

We get:

$10^{-pH}=H$

Now we substitute the given value of "pH = 4.5":

$10^{-4.5}=H$

Solving the operation:

$0.000032=H$

Therefore, the hydrogen ion concentration of the fluid is 0.000032

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3 years ago

Please help. Algebra.

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A conical water tank with vertex down has a radius of 14 feet at the top and is 28 feet high. If water flows into the tank at a

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2 years ago

Find the slope of each line. 1) (-1, 1), (-1, 4)

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Answer:

The line presented has an undefined slope.

Step-by-step explanation:

We are given two points of a line: (-1, 1) and (-1, 4).

Coordinate pairs in mathematics are labeled as (x₁, y₁) and (x₂, y₂).

The x-coordinate is the point at which if a straight, vertical line were drawn from the x-axis, it would meet that line.
The y-coordinate is the point at which if a straight, horizontal line were drawn from the y-axis, it would meet that line.

Therefore, we know that the first coordinate pair can be labeled as (x₁, y₁), so, we can assign these variables these "names" as shown below:

x₁ = -1
y₁ = 1

We also can use the same naming system to assign these values to the second coordinate pair, (-1, 4):

x₂ = -1
y₂ = 4

We also need to note the rules about slope. There are different instances in which a slope can either be defined or it cannot be defined.

Circumstance 1: As long as the slope is not equal to zero, there can be a

positive slope, $\frac{1}{3}$
negative slope, $-\frac{5}{6}$

Circumstance 2: If the slope is completely vertical (there is not a "run" associated with the line), there is an undefined slope. This is the slope of a vertical line. An example would be a vertical line (the slope is still zero).

Circumstance 3: If the line is a horizontal line (the line does not "rise" at all), then the slope of the line is zero.

Therefore, a slope can be positive, negative, zero, or undefined.

Now, we need to solve for the line we are given.

The slope of a line is determined from the slope-intercept form of an equation, which is represented as $\text{y = mx + b}$ .

The slope is equivalent to the variable m. In this equation, y and x are constant variables (they are always represented as y and x) and b is the y-intercept of the line.

We can do this by using the coordinates of the point and the slope formula given two coordinate points of a line: $m=\frac{y_2-y_1}{x_2-x_1}.$

Therefore, because we defined our values earlier, we can substitute these into the equation and solve for m.

Our values were:

x₁ = -1
y₁ = 1
x₂ = -1
y₂ = 4

Therefore, we can substitute these values above and solve the equation.

$\displaystyle{m = \frac{4 - 1}{-1 - -1}}\\\\m = \frac{3}{0}\\\\m = 0$

Therefore, we get a slope of zero, so we need to determine if this is a vertical line or a horizontal line. Therefore, we need to check to see if the x-coordinates are the same or if the y-coordinates are the same. We can easily check this.

x₁ = -1

x₂ = -1

y₁ = 1

y₂ = 4

If our y-coordinates are the same, the line is horizontal.

If our x-coordinates are the same, the line is vertical.

We see that our x-coordinates are the same, so we can determine that our line is a vertical line.

Therefore, finding that our slope is vertical, using our rules above, we can determine that our slope is undefined.

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