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OleMash [197]
2 years ago
13

Which expression is equivalent to 4x^2sqrt 5x^4 times 3sqrt 5x^8 , if x ≠ 0?

Mathematics
1 answer:
Elena L [17]2 years ago
5 0

The expression which is equivalent to 4x²√5x⁴ × 3√5x^8 is; 60x^8.

<h3>Which expression is equivalent to the given expression?</h3>

The expression given in the task content is; 4x²√5x⁴ × 3√5x^8.

Hence, upon evaluation of the product; we have;

= 12x²√25x¹².

= 60x^8.

Read more on square roots;

brainly.com/question/620307

#SPJ1

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3 square root of 721
NeTakaya

Answer:

La raíz cuadrada de 721  

Step-by-step explanation:

La Segunda Raíz o Raíz Cuadrada del número 721 es 26.8514431642

Esto se comprueba multiplicando 26.8514431642 por si mismo, debe arrojar como resultado 721

o en otro termino 721.9049245737

The Second Root or Square Root of the number 721 is 26.8514431642

This is proven by multiplying 26.8514431642 by itself, it must result in 721

or in another term 721.9049245737

5 0
4 years ago
What is the fraction 117/30 simplified as a mixed fraction
Nady [450]
117/30 = 3 remainer 27/30 (as 3 * 30 = 90)
= 3 + 9/10
6 0
4 years ago
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Help and the one with the best answer gets branlest.
adoni [48]

Answer:

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4 0
3 years ago
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Jevator has a weight limit of
Whitepunk [10]

Answer:

i think it would be 1550?

Step-by-step explanation:

im pretty sure you add teh weight of the three people and convert it to one ton

4 0
3 years ago
Directions: for questions 1 through 4, find the diagonal length of each solid figure.
Alex787 [66]
\text{The length of the diagonal is }11.2\text{ mm}

Here, we want to find the diagonal of the given solid

To do this, we need the appropriate triangle

Firstly, we need the diagonal of the base

To get this, we use Pythagoras' theorem for the base

The other measures are 6 mm and 8 mm

According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides

Let us have the diagonal as l

Mathematically;

\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}

Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above

Thus, we calculate this using the Pytthagoras' theorem as follows;

\begin{gathered} d^2=5^2+10^2 \\ d^2\text{ = 25 + 100} \\ d^2\text{ = 125} \\ d\text{ = }\sqrt[]{125} \\ d\text{ = }11.2\text{ mm} \end{gathered}

7 0
1 year ago
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